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aliina [53]
3 years ago
6

the perimeter of an equilateral triangle is 150cm. If the length of the altitude of the triangle is x√3cm, what is the value of

x?​

Mathematics
1 answer:
jenyasd209 [6]3 years ago
4 0

Answer:

X = 25

Step-by-step explanation:

To solve this question, we'll first of all find determine the side length of the triangle from the perimeter.

Perimeter of an equilaterial triangle = 3 * s

S = side length

Perimeter = 150cm

150 = 3s

S = 150 / 3

S = 50cm

The side lengths are 50cm each since they are all equal.

To find x,

We have to divide the triangle equally into two different part.

Check the first attachment for better illustration on how the equilaterial triangle is.

Check the second attachment for better illustration on the triangle when its divided into a right angle triangle.

From the right angle triangle, we can use pythagorean theorem to solve for x

a² = b² + c²

a = 50cm

b = 25cm

c = x√(3)

50² = [x√(3)]² + 25²

2500 = x² * 3 + 625

2500 - 625 = 3x²

1875 = 3x²

X² = 1875 / 3

X² = 625

X = √(625)

X = 25

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The measure of angle ABD is (0.15x+65) and the measure of angle CBD is(0.1x+28) . Find the value of x.
Andrej [43]

Answer:

x = 348

Step-by-step explanation:

The measure of angle ABD is (0.15x+65) and the measure of angle CBD is(0.1x+28) . Find the value of x.

0.15x + 65 + 0.1x + 28 = 180

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0.25x = 180 - 93

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3 years ago
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faust18 [17]

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Adding r on both sides, we get

17n+r + nx  = 34x - r+r.

17n + r + nx = 34x.

Subtracting nx from both sides, we get

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Factoring out gcf x on right side, we get

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Dividing both sides by (34-n), we get

\frac{(17x + r)}{(34-n)} = \frac{x(34-n)}{(34-n)}

\frac{(17x + r)}{(34-n)} = x

<h3>Therefore, final answer is x=\frac{(17x + r)}{(34-n)}.</h3>
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