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MAVERICK [17]
3 years ago
7

Brenda invests $4,848 in a savings account with a fix annual interest rate of 5% compounded 2 times per year.what will the accou

nt balance be after 6 years?
Mathematics
1 answer:
Nadya [2.5K]3 years ago
8 0

A = P(1 + rt)

A= 4,848(1+.05*6)

A=6302.4

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An online bookstore charges $2 to ship any book. Cole graphs the relationship that gives the total cost x dollarars. Name an ord
Nonamiya [84]
(0,2) because you must start off at $2
6 0
3 years ago
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The length of human pregnancies from conception to birth follows a distribution with mean 266 days and standard deviation 15 day
Katena32 [7]

Answer:

a) 81.5%

b) 95%

c) 75%

Step-by-step explanation:

We are given the following information in the question:

Mean, μ = 266 days

Standard Deviation, σ = 15 days

We are given that the distribution of  length of human pregnancies is a bell shaped distribution that is a normal distribution.

Formula:

z_{score} = \displaystyle\frac{x-\mu}{\sigma}

a) P(between 236 and 281 days)

P(236 \leq x \leq 281)\\\\= P(\displaystyle\frac{236 - 266}{15} \leq z \leq \displaystyle\frac{281-266}{15})\\\\= P(-2 \leq z \leq 1)\\\\= P(z \leq 1) - P(z < -2)\\= 0.838 - 0.023 = 0.815 = 81.5\%

b) a) P(last between 236 and 296)

P(236 \leq x \leq 281)\\\\= P(\displaystyle\frac{236 - 266}{15} \leq z \leq \displaystyle\frac{296-266}{15})\\\\= P(-2 \leq z \leq 2)\\\\= P(z \leq 2) - P(z < -2)\\= 0.973 - 0.023 = 0.95 = 95\%

c) If the data is not normally distributed.

Then, according to Chebyshev's theorem, at least 1-\dfrac{1}{k^2}  data lies within k standard deviation of mean.

For k = 2

1-\dfrac{1}{(2)^2} = 75\%

Atleast 75% of data lies within two standard deviation for a non normal data.

Thus, atleast 75% of pregnancies last between 236 and 296 days approximately.

7 0
3 years ago
Libanea bought tomatoes that cost $0.84 per pound. She paid $3.36 for the tomatoes. How many pounds of tomatoes did she buy?
muminat

Answer: 4 tomatoes

Step-by-step explanation:

Divide 3.36 by 0.84 = 4

8 0
2 years ago
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Evaluate 5+5*5+5/5-5+5*5
rewona [7]

Answer:

51

Step-by-step explanation:

5*5=25

5/5=1

5+25+1-5+25

30+1-5+25

31-5+25

26+25

51

4 0
3 years ago
Read 2 more answers
A ball of mass 0.4 kg flies through the air at low speed, so that air resistance is negligible. What is the net force acting on
arsen [322]

Answer:

-3.92 N

Step-by-step explanation:

We are given that

Mass of ball=0.4 kg

Acceleration due to gravity=-9.8m/s^2

Because the ball flies against to gravity

We have to find the net force acting on the ball while it is in motion.

We know that when there is no air resistance then the net  force acts on the ball is equal to weight of ball.

Net force,F =mg

Substitute the values then we get

F=0.4(-9.8)

F=-3.92N

Hence, the net force acting on the ball while it is on motion=-3.92 N

6 0
2 years ago
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