Anastasia’s mom baked a giant sugar cookie for her birthday. On her birthday, ⅝ of the birthday cookie was eaten. The next day h
1 answer:
Answer:
9/32 of the cookie was left for Stephanie to eat after lunch
Step-by-step explanation:
Anastasia’s mom baked a giant sugar cookie for her birthday.
On her birthday, ⅝ of the birthday cookie was eaten.
So, remaining cake =
The next day her brother ate ¼ of what remained.
Amount of cake eaten by her brother =
So, remaining cake =
Hence 9/32 of the cookie was left for Stephanie to eat after lunch
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Answer:
The real perimeter is:
And the area would be:
Step-by-step explanation:
For this case we know one side of a square given 6mm.
We can begin calculating the perimeter for the scale figure with this formula:
The area for this case is given by:
And we know that the drawing has a scale of 1 mm : 7 km and if we convert the perimeter to km we got:
And the area would be:
The functions are:
i)
ii)
.
We note that both Sin and Cos functions cannot produces values smaller than -1, or larger than 1.
In other words, the range of both these functions is [-1, 1].
Whatever expression A is, sin(A) and cos(A) are values in [-1, 1].
Assume
produced its maximal value, 1, then 
makes this value 3.
Thus, the maximum value of g(x) is 3, as can be also seen in the graph.
Similarly, assume cos(x) produced 1, then 2cos(x) makes it 2. Thus, the greatest value of f(x) is 2.
Answer: max{f(x)}=2, max{g(x)}=3, so g has the largest maximal value.
i)
ii)
We note that both Sin and Cos functions cannot produces values smaller than -1, or larger than 1.
In other words, the range of both these functions is [-1, 1].
Whatever expression A is, sin(A) and cos(A) are values in [-1, 1].
Assume
Thus, the maximum value of g(x) is 3, as can be also seen in the graph.
Similarly, assume cos(x) produced 1, then 2cos(x) makes it 2. Thus, the greatest value of f(x) is 2.
Answer: max{f(x)}=2, max{g(x)}=3, so g has the largest maximal value.