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Firdavs [7]
3 years ago
12

Simplify 3x + 6x^2 - 5x - x^2

Mathematics
2 answers:
just olya [345]3 years ago
8 0

Answer: -2x + 5x^2

Step-by-step explanation:

3x + 6x^2 - 5x - x^2 = x(3-5) + x^2(6-1) = -2x + 5x^2

Evgen [1.6K]3 years ago
5 0

Answer:

Answer = x ( 5x - 2)

Step-by-step explanation:

3x + 6x² - 5x - x²

Collect like terms

= 6x² - x² - 5x + 3x

= 5x² - 2x

= x ( 5x - 2)

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Given two angles that measure 50 degrees and 80 degrees and side that measures 4 feet, how many triangles, if any, can be constr
kirza4 [7]
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3 0
3 years ago
In order to help identify baby growth patterns that are unusual, we need to construct a confidence interval of the mean head cir
sukhopar [10]

Answer:

The 99% confidence interval estimate of the mean head circumference of all 2-month-old babies is (40.18cm, 41.02cm).

Step-by-step explanation:

Our sample size is 100.

The first step to solve this problem is finding our degrees of freedom, that is, the sample size subtracted by 1. So

df = 100-1 = 99.

Then, we need to subtract one by the confidence level \alpha and divide by 2. So:

\frac{1-\alpha}{2} = \frac{0.01}{2} = 0.005

Now, we need our answers from both steps above to find a value T in the t-distribution table. So, with 99 and 0.005 in the t-distribution table, we have T = 2.626

Now, we find the standard deviation of the sample. This is the division of the standard deviation by the square root of the sample size. So

s = \frac{1.6}{\sqrt{100}} = 0.16

Now, we multiply T and s

M = Ts = 2.626*0.16 = 0.42

For the lower end of the interval, we subtract the sample mean by M. So the lower end of the interval here is

L = 40.6 - 0.42 = 40.18cm

For the upper end of the interval, we add the sample mean and M. So the upper end of the interval here is

L = 40.6 + 0.42 = 41.02cm

So

The 99% confidence interval estimate of the mean head circumference of all 2-month-old babies is (40.18cm, 41.02cm).

3 0
3 years ago
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