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Mila [183]
3 years ago
5

Which polynomial is prime

Mathematics
1 answer:
dezoksy [38]3 years ago
4 0

Answer:

A prime polynomial is similar to a prime number: it cannot be factored. The binomial x^2 +1 cannot be factored using real numbers as coefficients.

Step-by-step explanation:

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Help a brother out :')​
koban [17]

Answer:

3

Step-by-step explanation:

f(x) = x^2 +4x

f(-3) = (-3)^2 +4(-3)

       =9-12

       =-3

|f(-3) | = |-3|

The absolute value is the positive value

|f(-3) | = 3

7 0
4 years ago
Read 2 more answers
The function f(x)=21,500(0.86)^x models the value of a car after x years. What is the yearly depreciation rate of the value of t
Serjik [45]

Answer:

The car loses 14 percent of its value each year.

Step-by-step explanation:

subtract .86 from 1 to get the value of depreciation

3 0
3 years ago
Rectangle ABCD is graphed in the coordinate plane. The following are the vertices of the rectangle: A(2, -6), B(5, -6), C(5, -2)
max2010maxim [7]

Answer:

Step-by-step explanation:

Refer the answer of brainly.com/question/17115212

3 0
3 years ago
Can you guys help me with this math questions
dimulka [17.4K]

Answer:

2)  $40 per shirt

3)  80/9 m = 8.9 m (nearest tenth)

Step-by-step explanation:

The first question has been answered here: brainly.com/question/27846862

------------------------------------------------------------------------------------------------------

<u>Question 2</u>

Given information:

  • Previous sales = 300 shirts at $20 each
  • For every $1 increase in price, the number of sales diminishes by 5

Let x = number of $1 increases

Let y = total revenue (in dollars)

From the given information:

  • Price change of shirt:  (20 + x)
  • Number of sales change:  (300 - 5x)

Therefore, we can create a <u>quadratic equation</u> with the given information:

\implies y = (20+x)(300-5x)

As we need to find the maximum amount of revenue, we need to find the vertex of y.  As the equation is already factored, the quickest way to do this is to the find the mid-point of the zeros (since a quadratic curve is symmetrical).

\begin{aligned}y & =0\\\implies (20+x)(300-5x) & =0\\\implies (20+x) & =0 \implies x=-20\\\implies (300-5x) & = 0 \implies x=60\end{aligned}

\textsf{Midpoint}=\dfrac{-20+60}{2}=20

Therefore, Sammy should have 20 $1 increases to maximize the revenue, so the new price will be:

\implies \$20 + 20 \times \$1 = \$40\: \sf per\:shirt

------------------------------------------------------------------------------------------------------

<u>Question 3</u>

Given information:

  • Bridge is modeled as a parabola
  • Width of bridge = 30 m
  • Max height of bridge = 10 m high (in the middle)

As the bridge is modeled as a parabola, and we have been given the width and height, we can create a quadratic equation using the vertex form.

Vertex form:  y=a(x-h)^2+k

where:

  • x is the horizontal distance of the bridge
  • y is the height of the bridge
  • (h, k) is the vertex
  • a is some constant

Middle of the bridge = 30 m ÷ 2 = 15 m

Max height of the bridge = 10 m

Therefore, the vertex of the parabola is (15, 10)

\implies y=a(x-15)^2+10

We know that when x = 0, y = 0.  Therefore, substitute these values into the equation and solve for a:

\implies 0=a(0-15)^2+10

\implies 0=225a+10

\implies 225a=-10

\implies a=-\dfrac{10}{225}

\implies a=-\dfrac{2}{45}

Therefore, the equation of the parabola is:

\implies y=-\dfrac{2}{45}(x-15)^2+10 \quad \quad \textsf{for }0\leq x\leq 30

The horizontal distance at 5 m right of the middle is:

\implies \dfrac{30}{2}+5=20\:\sf m

Therefore, to find the height at this point, input x=20 into the equation and solve for y:

\implies -\dfrac{2}{45}(20-15)^2+10=\dfrac{80}{9}\:\sf m

Therefore, the height of the bridge at 5 m to the right of the middle is:

\dfrac{80}{9}\:=8.9\: \sf m\:(nearest\:tenth)

3 0
2 years ago
A two digits number is 21 times the difference and 350% of the product of its digit. Find the quotient of the digit of number​
Juliette [100K]
The number is 63, so the quotient is 2.

Two digit numbers divisible by 21:
21, 42, 63, 84

21: 2-1 = 1 * 3.5 = 3.5
3.5*2*1 = 7 but 7 does not equal 21

42: 4-2 = 2 * 3.5 = 7
3.5*4*2 = 28 does not equal 42

63: 6-3 = 3*3.5 = 13.5
3.5*6*3 = 63 :)

Check:
21(6-3)=21(3)= 63 :)
3.5(6)(3) = 21(3) = 63 :)

63: 6/3 = 2
3 0
3 years ago
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