Answer:
Step-by-step explanation:
If you call "5x-2x^2+1" an "equation," then you must equate 5x-2x^2+1 to 0:
5x-2x^2+1 = 0
This is a quadratic equation. Rearranging the terms in descending order by powers of x, we get:
-2x^2 + 5x + 1 = 0. Here the coefficients are a = -2, b = 5 and c = 1.
Use the quadratic formula to solve for x:
First find the discriminant, b^2 - 4ac: 25 - 4(-2)(1) = 25 + 8 = 33
Because the discriminant is positive, the roots of this quadratic are real and unequal.
-b ± √(discriminant)
Applying the quadratic formula x = --------------------------------
2a
we get:
-5 ± √33 -5 + √33
x = ----------------- = --------------------- and
2(-2) -4
-5 - √33
---------------
-4
It’s b I’m positive because I did 1.25 to the power of 3 and put that into fractional form
Tell you the truth bro I don't know
The slope is 0, the equation is y=50
When the line is horizontal the slope is 0 and when the line is vertical the slope is undefined.
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❖ 16 min : 28 min simplified to a fraction is 
16 and 28 can both be divided by 24:
16 ÷ 4 = 4
28 ÷ 4 = 7
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