Answer:
C. 97.1 should be your answer
Step-by-step explanation:
Let r, g and b represent red, green and blue.
r+g+b = 74
r=g-1
b=r+g
Again, r+g+b = 74. Let's substitutte r+g for b: r+g+(r+g) = 74.
Next, let's eliminate r. Use r=g-1. Then g-1 + g + g-1 + g = 74
Combining the g terms, 4g - 2 = 74 => 4g = 76 => g = 19
Recall that r=g-1
and
b=r+g
Find r. If r=g-1, and g=19, then r = 19-1=18
Find b: b = r+g = 18+19=37
So there are 37 blue candies, 18 red candies and 19 green candies.
Check: 37+18+19=74 ??? Yes.
Question: Given that BE bisects ∠CEA, which statements must be true? Select THREE options.
(See attachment below for the figure)
m∠CEA = 90°
m∠CEF = m∠CEA + m∠BEF
m∠CEB = 2(m∠CEA)
∠CEF is a straight angle.
∠AEF is a right angle.
Answer:
m∠CEA = 90°
∠CEF is a straight angle.
∠AEF is a right angle
Step-by-step explanation:
Line AE is perpendicular to line CF, which is a straight line. This creates two right angles, <CEA and <AEF.
Angle on a straight line = 180°. Therefore, m<CEA + m<AEF = m<CEF. Each right angle measures 90°.
Thus, the three statements that must be TRUE are:
m∠CEA = 90°
∠CEF is a straight angle.
∠AEF is a right angle