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3 years ago

I NEED HELP SUPER BAD!!!!!!

Mathematics

1 answer:

Katarina [22]3 years ago

4 0

There is no solution because the two lines don't intersect.

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Does someone know the answer

Liono4ka [1.6K]

Apothem - a line from the center of a regular polygon at right angles to any of its sides.

Answer: A. Apothem

3 0

3 years ago

we believe that 42% of freshmen do not visit their counselors regularly. For this year, you would like to obtain a new sample to

Maksim231197 [3]

Answer:

A sample of 1077 is required.

Step-by-step explanation:

In a sample with a number n of people surveyed with a probability of a success of $\pi$ , and a confidence level of $1-\alpha$ , we have the following confidence interval of proportions.

$\pi \pm z\sqrt{\frac{\pi(1-\pi)}{n}}$

In which

z is the zscore that has a pvalue of $1 - \frac{\alpha}{2}$ .

The margin of error is of:

$M = z\sqrt{\frac{\pi(1-\pi)}{n}}$

42% of freshmen do not visit their counselors regularly.

This means that $\pi = 0.42$

98% confidence level

So $\alpha = 0.02$ , z is the value of Z that has a pvalue of $1 - \frac{0.02}{2} = 0.99$ , so $Z = 2.327$ .

How large of a sample size is required?

A sample size of n is required, and n is found when M = 0.035. So

$M = z\sqrt{\frac{\pi(1-\pi)}{n}}$

$0.035 = 2.327\sqrt{\frac{0.42*0.58}{n}}$

$0.035\sqrt{n} = 2.327\sqrt{0.42*0.58}$

$\sqrt{n} = \frac{2.327\sqrt{0.42*0.58}}{0.035}$

$(\sqrt{n})^2 = (\frac{2.327\sqrt{0.42*0.58}}{0.035})^2$

$n = 1076.8$

Rounding up:

A sample of 1077 is required.

3 0

3 years ago

Please help me find the total area of the composite figure below (geometry)

Akimi4 [234]

Answer:

lw + $\frac{1}{2}$ × π × $(\frac{l}{2} )^{2}$ ⇒ Answer D is correct

Step-by-step explanation:

First, let us find the area of the semi-circle.

Area = $\frac{1}{2}$ × π × r²

Given that,

diameter of the semi-circle is ⇒ l

∴ radius ⇒ l / 2

Let us find it now.

Area = $\frac{1}{2}$ × π × r²

Area = $\frac{1}{2}$ × π × $(\frac{l}{2} )^{2}$

Secondly, let us find the area of the rectangle.

Area = length × width

Given that,

length ⇒ l

width ⇒ w

Let us find it now.

Area = length × width

Area = l ×w

Area = lw

And now let us find the total area.

Total area = Area of the rectangle + Area of the semi - circle

Tota area = lw + $\frac{1}{2}$ × π × $(\frac{l}{2} )^{2}$

8 0

2 years ago

Juan is making a model out of rhombi. Each rhombus will be connected to the one before it. Each rhombus will be 6 inches tall an

love history [14]

He will need 12 sq. inches of Paper for each rhombus.

Given: 6 inches tall and 4 inches wide.

so, Length of the diagonals are 6 and 4 inches respectively.

Refer to figure.

The two diagonals cuts the rhombus into four equal parts, so

Area of one rhombus = 4 x (area of 1 part of the rhombus)

Now,

Area of 1 part of the rhombus = $\frac{1}{2}$ x 3 x 2

= 3 sq. inches

Area of one rhombus = 4 x 3 = 12 sq. inches

Hence, 12 sq. inches of Paper is needed for each rhombus.

Learn more about the "Finding the area of the rhombus" Here : brainly.com/question/10684261

#SPJ4

5 0

1 year ago

Read 2 more answers

Find the measure of angle r

guapka [62]

What is the the x’s value?

5 0

3 years ago