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Nat2105 [25]
3 years ago
12

Which of the following is a high-speed network dedicated to storage that connects different kinds of storage devices, such as ta

pe libraries and disk arrays so they can be shared by multiple servers? Select one: a. SSN b. ASP c. LAN d. SAN e. Grid
Computers and Technology
1 answer:
Montano1993 [528]3 years ago
8 0

Answer:

SAN

Explanation:

A Storage Area Network (SAN) is a high-speed sub network of shared storage devices. A SAN's architecture works in a way that makes all storage devices available to all servers on a LAN or WAN. As more storage devices are added to a SAN, they too will be accessible from any server in the larger network.

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let m be a positive integer with n bit binary representation an-1 an-2 ... a1a0 with an-1=1 what are the smallest and largest va
Ahat [919]

Answer:

Explanation:

From the given information:

a_{n-1} , a_{n-2}...a_o in binary is:

a_{n-1}\times 2^{n-1}  + a_{n-2}}\times 2^{n-2}+ ...+a_o

So, the largest number posses all a_{n-1} , a_{n-2}...a_o  nonzero, however, the smallest number has a_{n-2} , a_{n-3}...a_o all zero.

∴

The largest = 11111. . .1 in n times and the smallest = 1000. . .0 in n -1 times

i.e.

(11111111...1)_2 = ( 1 \times 2^{n-1} + 1\times 2^{n-2} + ... + 1 )_{10}

= \dfrac{1(2^n-1)}{2-1}

\mathbf{=2^n -1}

(1000...0)_2 = (1 \times 2^{n-1} + 0 \times 2^{n-2} + 0 \times 2^{n-3} + ... + 0)_{10}

\mathbf {= 2 ^{n-1}}

Hence, the smallest value is \mathbf{2^{n-1}} and the largest value is \mathbf{2^{n}-1}

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2 years ago
Compare and contrast between first and second generation of computer<br>​
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Read 2 more answers
Each week, the Pickering Trucking Company randomly selects one of its 30 employees to take a drug test. Write an application tha
Sati [7]

Answer:

Following are the program to this question:

import java.util.*; //import package

public class Main //defining class

{

 public static void main(String[] args) //defining main method

 {

   int testedEmployee; //defining integer variable

   for(int i = 1;i<=52;i++) //defining loop that counts from 1 to 52  

   {

     testedEmployee = 1 + (int) (Math.random() * 30); //using random method that calculate and hold value

     System.out.print(testedEmployee+"\t"); //print value

     if(i%4 == 0)//defining codition thats checks value is divisiable by 4  

     {

       System.out.println(); //print space

     }

   }

 }

}

Output:

please find the attachment.

Explanation:

In the given java program, a class Main is declared, inside the class, the main method is declared, in which an integer variable "testedEmployee", is declared, in the next line, the loop is declared, that can be described as follows:

  • Inside the loop, a variable "i" is declared, which starts from 1 and stop when its value is 52, inside the loop a random method is used, that calculates the random number and prints its value.
  • In the next step, a condition is defined, that check value is divisible 4 if this condition is true, it will print a single space.

3 0
3 years ago
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