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Orlov [11]
3 years ago
10

Factoring trinomials 10b × 2 + 17b + 3

Mathematics
1 answer:
Cerrena [4.2K]3 years ago
8 0
(I'm assuming the first term is 10 b squared)

The first thing you need to know before diving in is to find the factors of 10 and 3.
10 = 1x10, 2x5
3 = 1x3

Next you will have to find a combination that when multiplied the middle term is 17. In this case it is 2x5 and 1x3. We can test it out by setting it up in binomials.

(2b + 3)(5b + 1) = 10b squared + 2b + 15b + 3 = 10b squared + 17b + 3.
The reason why the binomials are additions is because both the middle and end terms are positive.

Hope this helps!
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The sum of the first 3 terms of a geometric series is 171 and the common ratio is 2/3
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==============================================

Work Shown:

a = first term

a*(2/3) = (2/3)a= second term

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Add up the three terms

a + (2/3)a + (4/9)a = (9/9)a + (6/9)a + (4/9)a = (19/9)a

Set this equal to 171, which is what we want the first three terms to sum to, then solve for 'a'

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------------------------------------

Checking the answer:

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(2/3)*a = (2/3)*81 = 54 = second term

(4/9)*a = (4/9)*81 = 36 = third term

adding up the three terms gets us

81+54+36 = 171

so we have confirmed the answer

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