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blsea [12.9K]
3 years ago
10

What is the volume of the cube? Cube with length, width, and height labeled as 9 inches.

Mathematics
2 answers:
iogann1982 [59]3 years ago
5 0

Answer:

729 inch³

Step-by-step explanation:

Volume of a cube = side³

= 9³

= 729 inch³

liberstina [14]3 years ago
3 0

Answer:

V=a^3

Step-by-step explanation:

The volume of a cube is found by multiplying the length, width, and height. A cube has the same length, width and height. In this case is it 9, so you multiply 9 by 9, three times, obtaining 729, which is your volume.

V=9^3

9x9x9

V=729

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Answer:

Step-by-step explanation:

Area = 1/2 b h

= 1/2 * 4 * 5

= 10 unit^2.

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How do you do literal equations with fractions?
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3 years ago
Translate the given phrase into an algebraic expression and simplify if possible: the product of -13 and the difference of c
Musya8 [376]

Answer:  -13c+13d

Step-by-step explanation:

For this exercise it is important to remember the following:

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3. The Distributive property states that:

a(b+c)=ab+ac\\\\a(b-c)=ab-ac

Keeping the above on mind, you know that:

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c-d

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-13(c-d)

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7 0
3 years ago
What is the unit rate of 183 miles in three hours
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3 0
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Read 2 more answers
Average Temperatures Suppose the temperature (degrees F) in a river at a point x meters downstream from a factory that is discha
mr Goodwill [35]

Answer:

Step-by-step explanation:

Average Temperatures Suppose the temperature (degrees F) in a river at a point x meters downstream from a factory that is discharging hot water into the river is given by

T(x) = 160-0.05x^2

a. [0, 10]

For x = 0

T(0) = 160 - 0.05 × 0^2

T(0) = 160

For x = 10

T(10) = 160 - 0.05 × 10^2

T(10) = 160 - 5 = 155

The average temperature

= (160 + 155)/2 = 157.5

b. [10, 40]

For x = 10

T(10) = 160 - 0.05 × 10^2

T(10) = 160 - 5 = 155

For x = 40

T(10) = 160 - 0.05 × 40^2

T(10) = 160 - 80 = 80

The average temperature

= (80 + 155)/2 = 117.5

c. [0, 40]

For x = 0

T(0) = 160 - 0.05 × 0^2

T(0) = 160

For x = 40

T(10) = 160 - 0.05 × 40^2

T(10) = 160 - 80 = 80

The average temperature

= (160 + 80)/2 = 120

6 0
3 years ago
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