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otez555 [7]
3 years ago
7

Please Help! I have 2 questions,

Mathematics
1 answer:
GrogVix [38]3 years ago
7 0
2. 5(x-1)=-3x+35
5x-5=-3x+35
5x=-3x+30
2x=30
x=15
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Which graph shows the solution to this system of inequalities?<br> y &lt; 2x + 4<br> y &gt; -X -3
Arturiano [62]

Answer:

The answer is Graph X.

  • Always start by isolating the variable \color{red}y on the left side of the inequality.
  • Change the inequality to equality symbol.
  • Graph the boundary line from step 2 in the XY-plane.
  • The last step is to shade one side or region of the boundary line.

Please Mark Brainliest If This Helped!

3 0
3 years ago
Write these numbers in order of size, start with the<br> smallest number<br><br> 60% 1/2 0.3 3/4 0.4
adoni [48]
(Smallest to biggest) 0.3, 0.4, 1/2, 60%, 3/4
Turning all number to decimals
.3, .4, .5, .60, .75
8 0
3 years ago
If the product of two number is 10 and the sum is 7 ,then the longest of the two number is​
irinina [24]

Answer:

5 units

Step-by-step explanation:

Step one:

Given data

Le the first number be x

and the second number be y

So

x*y= 10-----------------1

and

x+y= 7-----------------2

from eqn 1

x= 10/y

put x= 10/y in eqn 2

10/y+y= 7\\\\10/y= 7-y

cross multiply we have

10=y(7-y)\\\\10=7y-y^2

rearrange

y^2-7y+10=0

the factors of the quadratic expression are

-5 and -2

y^2-5y-2y+10= 0\\\\y(y-5)-2(y-5) =0\\\\y-2=0\\\\y= 2\\\\y-5= 0\\\\y=5\\\\

The longest side is 5 units

3 0
3 years ago
the ratio of clown fish to angel fish at a pet store is 5: 4. the ratio of angle fish to goldfish is4:3 there are 60 clown fish
denis23 [38]
Clown fish: angel fish    5:4
angle fish: gold fish      4:3

(60): angel fish=5:4
(5)(12)=60
(4)(12)=48 angel fish

(48): gold fish=4:3
(4)(12)=48
(3)(12)=36 gold fish

3 0
3 years ago
a laboratory, you determine that the density of a certain solid is 5.23×10−6kg/mm3. Convert this density into kilograms per cubi
Vedmedyk [2.9K]

Answer:

5.23\times 10^{-6}\ kg/mm^3=5230\ kg/m^3          

Step-by-step explanation:

Given : The density of a certain solid is 5.23\times 10^{-6} kg/mm³.

To find : Convert this density into kilograms per cubic meter ?

Solution :

We know that,

1\ m^3=10^9\ mm^3

or 10^9\ mm^3=1\ m^3

So, 1 mm^3=\frac{1}{10^9}\ m^3

1 mm^3=10^{-9}\ m^3

Converting 5.23\times 10^{-6} kg/mm³ into kg/m³,

5.23\times 10^{-6}\ kg/mm^3=\frac{5.23\times 10^{-6}}{10^{-9}}\ kg/m^3

5.23\times 10^{-6}\ kg/mm^3=5.23\times 10^{-6+9}\ kg/m^3

5.23\times 10^{-6}\ kg/mm^3=5.23\times 10^{3}\ kg/m^3

5.23\times 10^{-6}\ kg/mm^3=5230\ kg/m^3

Therefore, 5.23\times 10^{-6}\ kg/mm^3=5230\ kg/m^3

6 0
3 years ago
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