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3 years ago

PLEASE HELP ME! I keep getting the wrong answer.

1 answer:

7 0

<span>Given that f(x) = 5x − 1 and g(x) = 3x − 9, it is required to find the value of g(x) − f(x). g(x) − f(x) = [3x − 9] - [5x − 1]. - By substitution. = 3x - 5x -9 +1 -by simplifying and rearranging = -2x -8 -by solving = -2(x+4) -by taking out -2 as a factor of both terms. Hence either -2x -8 or -2(x+4) is the needed answer for finding the difference of the two given functions.</span>

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3 years ago

Read 2 more answers

Solve √5r - 9 - 3 = √r +4-2

Mekhanik [1.2K]

Answer:

r = 5

Step-by-step explanation:

Solving radical equations often results in extraneous solutions. These can be avoided by using a graphing calculator for the solution.

<h3>Graph</h3>

The attached shows that the value of r that makes both sides of the equation have the same value is r = 5.

<em>Check:</em>

√(5·5 -9) -3 = √(5 +4) -2 ⇒ 4 -3 = 3 -2 . . . true

<h3>Analytical solution</h3>

Solution of an equation like this is typically done by isolating the radical expressions, then squaring the equation.

We can add 3, square the equation, then isolate the radical and square again:

$\displaysyle \sqrt{5r-9}-3=\sqrt{r+4}-2\\\\\sqrt{5r-9}=\sqrt{r+4}+1\qquad\text{add 3}\\\\5r-9=(r+4)+2\sqrt{r+4}+1\qquad\text{square both sides}\\\\(4r-14)^2=4(r+4)\qquad\text{subtract $(r+5)$ and square again}\\\\16r^2-116r+180=0\qquad\text{rewrite in standard form}\\\\4(4r -9)(r -5) = 0\qquad\text{factor}\\\\r=\{\dfrac{9}{4},\ 5\}\qquad\text{solutions to the factored form}$

Trying these values in the original equation, we get ...

√((5(9/4) -9) -3 = √(9/4 +4) -2 ⇒ 1.5 -3 = 2.5 -2 . . . . . false

√(5(5) -9) -3 = √(5 +4) -2 ⇒ 4 -3 = 3 -2 . . . . . true

The solution is r = 5.

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3 years ago

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Leya [2.2K]

Answer:

so bro imma help you

Step-by-step explanation:

the answer is 37/12

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3 years ago

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Svet_ta [14]

Answer:

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Step-by-step explanation:

Nuestra ecuación será: 3 + 8x + 3x

No sabemos qué es x, así que simplemente sumamos términos semejantes y obtenemos 3 + 11x

Espero que esto haya ayudado, por favor marque lo más inteligente, ¡gracias!

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3 years ago