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rjkz [21]
4 years ago
13

PLEASE HELP ME!!! I would really appreciate it!

Mathematics
1 answer:
bazaltina [42]4 years ago
8 0
Hey there!
I just worked it out and the answer is D. 4y^2-10y-1

I’ve just studied these long equations and then having to simplify the expressions in algebra. I really hope my answer benefits you in the best way!
~Brooke❤️
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Select all of the situations which can be represented by the expression 25.75x + 10.
Volgvan

Answer:

1,2,4

Explanation to the answer:

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4 years ago
Please help on this!!!
vivado [14]

Answer: 25 students

Step-by-step explanation:

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3 years ago
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A rectangle is nine inches longer than it is wide, and its diagonal is 10 inches longer than its width. What is the width of the
SashulF [63]
L = length

w = width

r = diagonal, or hypotenuse

In order to solve this, you must use the Pythagorean theorem (a^2 + b^2 = c^2)

L = w + 9 = a

w = ? = b

r = 10 + w = c

Solve like so:

a^2 + b^2 = c^2

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w^2 + 18w + 81 + w^2 = w^2 + 20w + 100

2w^2 + 18w + 81 = w^2 + 20w + 100

w^2 + 18w + 81 = 20w + 100

w^2 + 81 = 2w + 100

w^2 - 19 = 2w

2 = w - 19/w

w = 2 + 19/w

w ends up being equal to 5.47 as a decimal answer. The work to solve this equation further would require me to spend another couple hours to present. So if you wish to see how this is done, go to quickmath.com.
5 0
3 years ago
Evaluate the spherical coordinate integral
expeople1 [14]

Rewrite the equations of the given boundary lines:

<em>y</em> = -<em>x</em> + 1  ==>  <em>x</em> + <em>y</em> = 1

<em>y</em> = -<em>x</em> + 4  ==>  <em>x</em> + <em>y</em> = 4

<em>y</em> = 2<em>x</em> + 2  ==>  -2<em>x</em> + <em>y</em> = 2

<em>y</em> = 2<em>x</em> + 5  ==>  -2<em>x</em> + <em>y</em> = 5

This tells us the parallelogram in the <em>x</em>-<em>y</em> plane corresponds to the rectangle in the <em>u</em>-<em>v</em> plane with 1 ≤ <em>u</em> ≤ 4 and 2 ≤ <em>v</em> ≤ 5.

Compute the Jacobian determinant for this change of coordinates:

J=\begin{bmatrix}\frac{\partial u}{\partial x}&\frac{\partial u}{\partial y}\\\frac{\partial v}{\partial x}&\frac{\partial v}{\partial y}\end{bmatrix}=\begin{bmatrix}1&1\\-2&1\end{bmatrix}\implies|\det J|=3

Rewrite the integrand:

-3x+4y=-3\cdot\dfrac{u-v}3+4\cdot\dfrac{2u+v}3=\dfrac{5u+7v}3

The integral is then

\displaystyle\iint_R(-3x+4y)\,\mathrm dx\,\mathrm dy=3\iint_{R'}\frac{5u+7v}3\,\mathrm du\,\mathrm dv=\int_2^5\int_1^45u+7v\,\mathrm du\,\mathrm dv=\boxed{333}

5 0
4 years ago
Help asap plsplspls!! :)
OlgaM077 [116]

Answer:

1.7

Step-by-step explanation:

1 + 7/10

= 1 + 0.7

= 1.7

6 0
3 years ago
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