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ElenaW [278]
3 years ago
5

What is the sum of the polynomials 5 a squared b plus 2a squared b squared 5 a2b+2a2b2 and negative ab squared plus a squared b

squared−ab2+a2b2​?
Mathematics
1 answer:
cupoosta [38]3 years ago
3 0

The first polynomial is 5a^2b+2a^2b^2

The other polynomial is -ab^2+a^2b^2

Now to add polynomials we must add or subtract like terms

Adding them we have

(5a^2b+2a^2b^2)+(-ab^2+a^2b^2)

5a^2b+2a^2b^2-ab^2+a^2b^2

Here 2a^2b^2 $ and $ a^2b^2 $ are like terms $

So we add then

We get

5a^2b+3a^2b^2-ab^2

The addition of the polynomial is 5a^2b+3a^2b^2-ab^2


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Point A is at (-2,4) and point C is at (4,7). Find the coordinates of point B on AC such that the ratio of a B to a C is 1:3
Diano4ka-milaya [45]

Answer:

[x=\frac{1(4)+3(-2)}{1+3}, y=\frac{1(7)+3(4)}{1+3}]

[x=\frac{4-6}{4}, y=\frac{7+12}{4}]

[x=\frac{-2}{4}, y=\frac{19}{4}]

[x=-0.5, y=4.75]

Therefore, the coordinates of point 'b' would be (-0.5 , 4.75).

Step-by-step explanation:

We have been given that point a is at   (-2,4) and point c is at   (4,7) .

We are asked to find the coordinates of point b on segment ac such that the ratio is 1:3.

We will use section formula to solve our given problem.

When point P divides a segment internally in the ratio m:n, the coordinates of point P would be:

[x=\frac{mx_2+nx_1}{m+n}, y=\frac{my_2+ny_1}{m+n}]

\texttt{Let point} (-2,4)=(x_1,y_1) \texttt {and point} (4,7)=(x_2,y_2).

[x=\frac{1(4)+3(-2)}{1+3}, y=\frac{1(7)+3(4)}{1+3}]

[x=\frac{4-6}{4}, y=\frac{7+12}{4}]

[x=\frac{-2}{4}, y=\frac{19}{4}]

[x=-0.5, y=4.75]

Therefore, the coordinates of point 'b' would be (-0.5 , 4.75).

5 0
3 years ago
The length of C. D. Akers rectangular garden is 37 feet shorter than six times the width. If the perimeter of
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Answer:

  17 feet by 65 feet

Step-by-step explanation:

If w represents the width of the garden, then 6w-37 is the length. The perimeter of a rectangle is twice the sum of length and width, so the perimeter is ...

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  238 = 14w

  238/14 = w = 17

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  6w-37 = 6·17 -37 = 65

The width of the garden is 17 feet; the length is 65 feet.

3 0
3 years ago
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