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Lana71 [14]
3 years ago
14

Length of a school bus??

Mathematics
2 answers:
Fofino [41]3 years ago
8 0
Forty-five is the answer (:
Bezzdna [24]3 years ago
3 0
45 feet is the lenth of a school bus
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15x=33, what is the value of x?
DENIUS [597]

Answer:

2.2

Step-by-step explanation:

4 0
3 years ago
1 100 15 ? + 50 1 ? +1.175=1, start fraction, 15, divided by, 100, end fraction, plus, start fraction, 1, divided by, 50, end fr
tiny-mole [99]

Answer:

1.345

Step-by-step explanation:

I think the question you are trying to ask is (15/100) + (1/50) + (1.175) =

Convert all the fractions which includes 15/100 and 1/50 to decimals

Thus we have 15/100 = 0.15 and 1/50 = 0.02

The question is: 0.15 + 0.02 + 1.175 = 1.345

3 0
3 years ago
Read 2 more answers
Sid intended to type a seven-digit number, but the two 3's he meant to type did not appear. What appeared instead was the five-d
Karo-lina-s [1.5K]

Answer: D. 21ways.

Step-by-step explanation:

This is based on selection, fixing two '3' numbers into 5numbers to make it 7 numbers can be done in 7C2 ways.

Generally, nCr = n!/(n-r)!r!

7C2 = 7!/(7-2)!2!

=7!/5!2!

=7×6×5!/5!×2!

=7×6/2

=21ways (D)

3 0
3 years ago
There are 40 nickels in a roll. If you have 50 rolls of nickels, how many nickels do you have?
Shalnov [3]

2000

2000 because 50*40=2000

8 0
4 years ago
Find the critical points of the surface f(x, y) = x3 - 6xy + y3 and determine their nature.​
Vedmedyk [2.9K]

Compute the gradient of f.

\nabla f(x,y) = \left\langle 3x^2 - 6y, -6x + 3y^2\right\rangle

Set this equal to the zero vector and solve for the critical points.

3x^2-6y = 0 \implies x^2 = 2y

-6x+3y^2=0 \implies y^2 = 2x \implies y = \pm\sqrt{2x}

\implies x^2 = \pm2\sqrt{2x}

\implies x^4 = 8x

\implies x^4 - 8x = 0

\implies x (x-2) (x^2 + 2x + 4) = 0

\implies x = 0 \text{ or } x-2 = 0 \text{ or } x^2 + 2x + 4 = 0

\implies x = 0 \text{ or } x = 2 \text{ or } (x+1)^2 + 3 = 0

The last case has no real solution, so we can ignore it.

Now,

x=0 \implies 0^2 = 2y \implies y=0

x=2 \implies 2^2 = 2y \implies y=2

so we have two critical points (0, 0) and (2, 2).

Compute the Hessian matrix (i.e. Jacobian of the gradient).

H(x,y) = \begin{bmatrix} 6x & -6 \\ -6 & 6y \end{bmatrix}

Check the sign of the determinant of the Hessian at each of the critical points.

\det H(0,0) = \begin{vmatrix} 0 & -6 \\ -6 & 0 \end{vmatrix} = -36 < 0

which indicates a saddle point at (0, 0);

\det H(2,2) = \begin{vmatrix} 12 & -6 \\ -6 & 12 \end{vmatrix} = 108 > 0

We also have f_{xx}(2,2) = 12 > 0, which together indicate a local minimum at (2, 2).

3 0
2 years ago
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