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2 years ago

15x=33, what is the value of x?

Mathematics

1 answer:

DENIUS [597]2 years ago

4 0

Answer:

2.2

Step-by-step explanation:

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Answer:

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Step-by-step explanation:

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X ÷ 4 =6 need to find x please help

Sonja [21]

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Find C.

nasty-shy [4]

Answer:

$C=69.1^{\circ}$

Step-by-step explanation:

The Law of Cosines is given as:

$c^2=a^2+b^2-2ab\cos C$ .

Plugging in given values, we get:

$16^2=8^2+17^2-2\cdot 8\cdot 17\cdot \cos C,\\\cos C=\frac{-97}{-272},\\C=\arccos(\frac{97}{272}),\\C=\fbox{$69.1^{\circ}$}$ .

3 0

2 years ago

a spherical balloon is deflated at a rate of 256pi/3 cm^3/sec. at what rate is the radius of the balloon changing when the radiu

Hunter-Best [27]

What you need to look for is $\frac { dr }{ dt }$ when r=8.

Now:

$Volume\quad of\quad a\quad sphere:\\ \\ V=\frac { 4 }{ 3 } \pi { r }^{ 3 }$

$\therefore \quad \frac { dV }{ dr } =\frac { 4 }{ 3 } \pi \cdot 3{ r }^{ 2 }=4\pi { r }^{ 2 }\\ \\ \therefore \quad \frac { dr }{ dV } =\frac { 1 }{ \frac { dV }{ dr } } =\frac { 1 }{ 4\pi { r }^{ 2 } }$

$And:\\ \\ \frac { dV }{ dt } =-\frac { 256\pi }{ 3 } \\ \\ Therefore:\\ \\ \frac { dr }{ dt } =\frac { dr }{ dV } \cdot \frac { dV }{ dt }$

$\\ \\ =\frac { 1 }{ 4\pi { r }^{ 2 } } \cdot -\frac { 256\pi }{ 3 } \\ \\ =-\frac { 256 }{ 12 } \cdot \frac { \pi }{ \pi } \cdot \frac { 1 }{ { r }^{ 2 } }$

$\\ \\ =-\frac { 64 }{ 3{ r }^{ 2 } } \\ \\ When\quad r=8,\\ \\ \frac { dr }{ dt } =-\frac { 64 }{ 3\cdot { 8 }^{ 2 } } =-\frac { 1 }{ 3 } \\ \\ Answer:\quad -\frac { 1 }{ 3 } \quad cm/sec$

3 0

2 years ago

1) Bob weighed 200 lbs, but after dieting for 6 months, he weighed 170 lbs.

aivan3 [116]

Answer: 15%

Step-by-step explanation:

The Percentage decrease will be:

= Decrease in weight / Old weight × 100

= (200 - 170) / 200 × 100

= 30/200 × 100

= 15%

The Percentage decrease is 15%

7 0

2 years ago