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aleksklad [387]
3 years ago
12

Simplify

Mathematics
1 answer:
ikadub [295]3 years ago
3 0

Answer: (A)=10x5−29x4+33x3−18x2−18x+27

Step-by-step explanation:

How i solved it was by simplifying each answer there was available and (A) was the most compatiable answer!

=(2x+−3)(5x4+−7x3+6x2+−9)

=(2x)(5x4)+(2x)(−7x3)+(2x)(6x2)+(2x)(−9)+(−3)(5x4)+(−3)(−7x3)+(−3)(6x2)+(−3)(−9)

=10x5−14x4+12x3−18x−15x4+21x3−18x2+27

=10x5−29x4+33x3−18x2−18x+27

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\huge\text{Hey there!}

\huge\text{7*(-3) * (-2)(2) = ?}

\huge\text{7 * (-3) = -21}

\huge\text{-21 * (-2)2 = ?}

\huge\text{-21 * -2 = 42}

\huge\text{42(2) = ?}

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7 0
3 years ago
Jillian burns 187 calories when she runs 2 miles. How many miles will she
dedylja [7]

Answer:

I think jillian will have to run 10 miles

Step-by-step explanation:

2 miles = 100 calories

in order to burn 500 calories

2 miles = 100 calories burned

4 miles = 200 calories burned

6 miles = 300 calories burned

8 miles  = 400 calories burned

10 miles = 500 calories burned

7 0
3 years ago
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Different sizes of string needs to be cut to go around various shapes. All of the following sizes are in inches.
Brilliant_brown [7]

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first one

Step-by-step explanation:

6 0
3 years ago
Three friends go grocery shopping together and each buys same kind of oranges. Lamar buys 2 pounds and pays 7.00 Enrico buys 3 p
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8 0
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The rate of change of the number of mountain lions N(t) in a population is directly proportional to 725 - N(t), where t is the t
wolverine [178]

Answer:

a) The implied differential equation is \frac{dN}{725 - N} = kdt

b) The general equation is N = 725 - C e^{-kt}

c) The particular equation is N = 725 - 325 e^{-0.49t}

d) The population when t = 5, N(5) = 697 = 700( to the nearest 50)

Step-by-step explanation:

The rate of change of N(t) can be written as dN/dt

According to the question, \frac{dN}{dt} \alpha (725 - N(t))

\frac{dN}{dt} = k (725 - N)\\\frac{dN}{725 - N} = kdt

Integrating both sides of the equation

\int {\frac{1 }{725 - N}} \, dN  = \int {k} \, dt\\- ln (725 - N) = kt + C\\ ln (725 - N) = -(kt + C)\\725 - N = e^{-(kt + C)} \\725 - N = e^{-kt} * e^{-C} \\725 - N = C e^{-kt}\\N = 725 - C e^{-kt}

When t = 0, N = 400

400 = 725 - C e^{-k*0}\\400 = 725 - C\\C = 725 - 400\\C = 325

When t = 3,  N = 650

650 = 725 - (325 * e^{-3k})\\325 * e^{-3k} = 75\\e^{-3k} = 75/325\\e^{-3k} = 0.23\\-3k = ln 0.23\\-3k = -1.47\\k = 1.47/3\\k = 0.49

The equation for the population becomes:

N = 725 - 325 e^{-0.49t}

At t = 5, the population becomes:

N = 725 - 325 e^{-0.49*5}\\N = 725 - 325 e^{-2.45}\\N = 696.95\\N(5) = 697

N(5) = 700 ( to the nearest 50)

6 0
3 years ago
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