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2 years ago

Using the picture below, which angle is alternate exterior to angle 2?

Mathematics

1 answer:

zysi [14]2 years ago

7 0

It’s 7 because it is on the exterior, and the other side, of the the parallel lines from 2.

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The volume of a cube is 27 cubic meters. What is its surface area, in square meters?

stiks02 [169]

Step-by-step explanation:

the volume of a cube is

side³.

since the volume is 27 m³, the individual side lengths are then the cubic root of 27 = 3 m.

the surface area is 6 squares of 3×3 = 9m², so in total

9 × 6 = 54 m²

8 0

2 years ago

Solve for x in the equation x^2+20+100=36

Nesterboy [21]

This is what I found in a calculator

3 0

3 years ago

hi, i dont undertand number 20 because i was absent in class today and i rerally need help, i will appraciate with the help, and

Mariulka [41]

Given:

The equation is,

$2\log _3x-\log _3(x-2)=2$

Explanation:

Simplify the equation by using logarthimic property.

$\begin{gathered} 2\log _3x-\log _3(x-2)=2 \\ \log _3x^2-\log _3(x-2)=2_{}\text{ \lbrack{}log(a)-log(b) = log(a/b)\rbrack} \\ \log _3\lbrack\frac{x^2}{x-2}\rbrack=2 \end{gathered}$

Simplify further.

$\begin{gathered} \log _3\lbrack\frac{x^2}{x-2}\rbrack=2 \\ \frac{x^2}{x-2}=3^2 \\ x^2=9(x-2) \\ x^2-9x+18=0 \end{gathered}$

Solve the quadratic equation for x.

$\begin{gathered} x^2-6x-3x+18=0 \\ x(x-6)-3(x-6)=0 \\ (x-6)(x-3)=0 \end{gathered}$

From the above equation (x - 6) = 0 or (x - 3) = 0.

For (x - 6) = 0,

$\begin{gathered} x-6=0 \\ x=6 \end{gathered}$

For (x - 3) = 0,

$\begin{gathered} x-3=0 \\ x=3 \end{gathered}$

The values of x from solving the equations are x = 3 and x = 6.

Substitute the values of x in the equation to check answers are valid or not.

For x = 3,

$\begin{gathered} 2\log _3(3^{})-\log _3(3-2)=2 \\ 2\log _33-\log _31=2 \\ 2\cdot1-0=2 \\ 2=2 \end{gathered}$

Equation satisfy for x = 3. So x = 3 is valid value of x.

For x = 6,

$\begin{gathered} 2\log _36-\log _3(6-2)=2 \\ 2\log _36-\log _34=2 \\ \log _3(6^2)-\log _34=2 \\ \log _3(\frac{36}{4})=2 \\ \log _39=2 \\ \log _3(3^2)=2 \\ 2\log _33=2 \\ 2=2 \end{gathered}$

Equation satifies for x = 6.

Thus values of x for equation are x = 3 and x = 6.

6 0

1 year ago

Pls help me! (question is in the picture)

Savatey [412]

Answer:

getting the wrong answer or not using the correct symbols

Step-by-step explanation:

4 0

2 years ago

Read 2 more answers

The weekly demand for DVDs manufactured by a certain media corporation is given by

djverab [1.8K]

Let the production level that will yield a maximum profit for the manufacturer be x.
The unit price of the disc is given by p = -0.0006x^2 + 65.
The revenue from selling x discs (R(x)) = px = -0.0006x^3 + 65x

Profit = Revenue - Cost = -0.0006x^3 + 65x - (-0.002x^2 + 13x + 4000) = -0.0006x^3 + 0.002x^2 + 52x - 4000

For maximum profit, dP/dx = 0
-0.0018x^2 + 0.004x + 52 = 0
Using quadratic formular, x = 171

Therefore, the production level that will yield a maximum profit for the manufacturer is 171 discs.

8 0

3 years ago