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Nezavi [6.7K]
3 years ago
13

Two boxes of apples contain a total of 24 apples. If you have large number of apples in the first box and add 4 apples to the se

cond box, the total changes to apples. How many apples are in each box initially?
Mathematics
1 answer:
Ivahew [28]3 years ago
3 0
Answer.
24+4=28
28÷2=14
14 apples in each box.
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Can someone answer this question please please help me I really need it if it’s correct I will mark you brainliest .
mart [117]

Step 1) Divide the figure into separate shapes

Large rectangle: 8 x 9

Medium rectangle: 4 x 6

Quarter circle: r = 3

Step 2) Find the area of each shape

Large rectangle: A = 8 x 9 = 72

Medium rectangle: A = 4 x 6 = 24

Quarter circle: A = 1/4 x 3.14 x 3^2 = 7.065 + 3 = 10.065

Step 3) Add the areas together

A = 72 + 24 + 10.065 = 106.065 square millimeters (may need to round to 106.07, but rounding not given in the problem)

Hope this helps! :)

3 0
3 years ago
Read 2 more answers
What is the value of g
kompoz [17]

Answer:

27 degrees

Step-by-step explanation:

So basically 52.1 and g is the same as 79.1 so your equation is 52.1+g=79.1

So first you would subtract 52.1 from both sides g=27

Then basically you have the answer

So therefore g=27

5 0
3 years ago
What is the proper seperation of factors for this equation ∛24n² × ∛36n²
Gwar [14]

Answer:

{ \tt{ \sqrt[3]{24 {n}^{2}  }  \times  \sqrt[3]{36 {n}^{2} } }} \\  = { \tt{(  {n}^{ \frac{2}{3} })( \sqrt[3]{864})  }}

8 0
3 years ago
xP(x)00.2510.0520.1530.55Find the standard deviation of this probability distribution. Give your answer to at least 2 decimal pl
Nookie1986 [14]

The Solution:

Given:

Required:

Find the standard deviation of the probability distribution.

Step 1:

Find the expected value of the probability distribution.

E(x)=\mu=\sum_{i\mathop{=}0}^3x_iP_(x_i)\begin{gathered} \mu=(0\times0.25)+(1\times0.05)+(2\times0.15)+(3\times0.55) \\  \\ \mu=0+0.05+0.30+1.65=2.0 \end{gathered}

Step 2:

Find the standard deviation.

Standard\text{ Deviation}=\sqrt{\sum_{i\mathop{=}0}^3(x_i-\mu)^2P_(x_i)}=(0-2)^2(0.25)+(1-2)^2(0.05)+(2-2)^2(0.15)+(3-2)^2(0.55)=4(0.25)+1(0.05)+0(0.15)+1(0.55)=1+0.05+0+0.55=1.60

Thus, the standard deviation is 1.60

Answer:

1.60

8 0
1 year ago
Is (4•6)^3 equivalent to 4•6^3
Pani-rosa [81]
No because the exponent on 6^3 is 216 and if you use (4•6)^3 then you’ll have to multiply the quotations and then Square it to the third
4 0
4 years ago
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