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3 years ago

Express 11.6311.6311, point, 63 as a mixed number

Mathematics

1 answer:

grin007 [14]3 years ago

5 0

Answer:

jdjjdjeo

Step-by-step explanation:

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Initial value problems dy/dx+2y=3. Y(0)=1

Pavel [41]

The initial value equation is $y = \frac 12(3 - e^{-2x})$

<h3>How to solve the initial value?</h3>

The equation is given as:

$\frac{dy}{dx} +2y = 3$

Where

Y(0) = 1

Subtract 2y from both sides in the equation

$\frac{dy}{dx} = -2y + 3$

Rewrite as:

$\frac{dy}{-2y + 3} = dx$

Integrate both sides of the equation

$-\frac 12\ln|-2y + 3| = x + C_o$

Multiply through by -2

$\ln|-2y + 3| = -2x + C_1$

Take the exponent of both sides

$-2y + 3 = Ce^{-2x$

Next, we solve for C under the initial condition Y(0) = 1.

This gives

$-2(1) + 3 = Ce^{-2 * 0$

Evaluate

-2 + 3 = C

Solve for C

C = 1

Substitute C = 1 in $-2y + 3 = Ce^{-2x$

$-2y + 3 = e^{-2x$

Next, we solve for y

$y = \frac 12(3 - e^{-2x})$

Hence, the initial value equation is $y = \frac 12(3 - e^{-2x})$

Read more about initial value at:

brainly.com/question/16945606

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3 0

1 year ago

8) Ninety-one is 65% of what number?

lutik1710 [3]

Answer : 140
140 times 40% = 65 so the answer is 140

4 0

3 years ago

Read 2 more answers

In ΔNOP, \overline{NP}

lesya692 [45]

Answer:

x=11

Step-by-step explanation:

Using the Exterior Angle Theorem. . .

(3x+8) + (2x+9) = (8x-16)

Solve to get x = 11

3 0

3 years ago

Read 2 more answers

Which diagram shows the 3d shape out of these on the photo.

sleet_krkn [62]

Answer:

Step-by-step explanation:

The front elevation, side elevation, and plan of the 3D shape represent the shape C.

4 0

3 years ago

dos aviones parten de una ciudad con direcciones S32°E y E57°N¿ cuál es el angulo que forma sus direcciones?

Elan Coil [88]

Answer:

El ángulo formado entre las dos direcciones es aproximadamente 115º.

Step-by-step explanation:

Las direcciones dadas en el enunciado significan lo siguiente:

S32ºE - <em>32º al este del sur.</em>

E57ºN - <em>57º al norte del este.</em>

Vectorialmente hablando, cada dirección es la siguiente:

S32ºE

$A(x,y) = (\sin 32^{\circ}, -\cos 32^{\circ})$

$A(x,y) = (0.530, -0.848)$

E57ºN

$B(x,y) = (\cos 57^{\circ},\sin 57^{\circ})$

$B(x,y) = (0.545, 0.839)$

El ángulo formado entre los dos vectores unitarios ( $\theta$ ), medido en grado sexagesimales, puede determinarse mediante la siguiente ecuación vectorial:

$\theta = \cos^{-1} \frac{A\,\bullet \,B}{\|A\|\cdot \|B\|}$

Donde:

$\|A\|$ - Norma de $A(x,y)$ .

$\|B\|$ - Norma de $B(x,y)$ .

Si sabemos que $A(x,y) = (0.530, -0.848)$ , $B(x,y) = (0.545, 0.839)$ , $\|A\| = 1$ y $\|B\| = 1$ , entonces el ángulo formado entre los dos vectores es:

$\theta = \cos^{-1} \frac{(0.530)\cdot (0.545)+(-0.848)\cdot (0.839)}{(1)\cdot (1)}$

$\theta \approx 115^{\circ}$

El ángulo formado entre las dos direcciones es aproximadamente 115º.

4 0

3 years ago