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vichka [17]
3 years ago
9

Greater than or less than

Mathematics
1 answer:
34kurt3 years ago
5 0

Answer:

for what ? put your question completely

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Merry Christmas Eve Eve everyone! i can't wait to celebrate the birth of Jesus Christ! i appreciate Jesus Christ dying on the cr
Sidana [21]

I know I’m late but

WOOOOOOOOOOOOOOOOO JESUS!!!

Can’t wait for next year Haha!!!

3 0
3 years ago
You get a 5% commission. You base your monthly salary on $100000 in sales. What is your monthly salary.​
Natali [406]

Answer:

100/100'000*5 = 5000 + base commission of 100'000 = 105'000

Step-by-step explanation:

3 0
3 years ago
How to solve -2(v-2)=-3-2v i need it step by step
Goryan [66]

Answer:O0

Step-by-step explanation:

2*(v-2)-(-3-2*v)=0

STEP

1

:

Equation at the end of step 1

(0 - 2 • (v - 2)) - (-2v - 3) = 0

STEP

2

:

Equation at the end of step 2

7 = 0

STEP

3

:

Equations which are never true:

3.1 Solve : 7 = 0

3 0
3 years ago
Read 2 more answers
Please help me i know this might take a while but plz my teacher be buggin <br> Due today
trasher [3.6K]

Answer:

5) Part A: The rate of change, also known as the slope, is the "0.6x" part of the equation. It means that for every week the puppy is alive, x, that number is multiplied by 0.6 pounds.

Part B: The y-intercept is 4 pounds, which represents a puppy being 4 pounds at birth.

Part C: y = 0.6x + 4

y = 0.6(8)+4

y = 8.8

At 8 weeks, a puppy is estimated to be 8.8 pounds.

Part D: y = 0.6x + 4

22 = 0.6 + 4

-4              -4

18 = 0.6x

18/0.6 = 0.6x/0.6

30 = x

It would take a puppy 30 weeks to reach 22 pounds.

8 0
3 years ago
A piece of cardboard measures 10 ft by 10 ft. Four equal squares of size x are removed from the corners. After removing the squa
Gnesinka [82]

Answer:

The value of x would be \frac{5}{3}

Step-by-step explanation:

Given,

The dimension of the cardboard = 10 ft by 10 ft,

∵ After removing four equal squares of size x ( in ft ) from the corners,

The dimension of the resultant box would be,

Length = ( 10 - 2x ) ft,

Width = ( 10 - 2x ) ft,

Height = x ft,

The volume of box,

V=(10-2x)\times (10 - 2x)\times x=x(10-2x)^2 = x(100 - 40x + 4x^2)=100x - 40x^2 + 4x^3

Differentiating with respect to x,

V'=100 - 80x + 12x^2

Again differentiating with respect to x,

V''=-80 + 24x

For maxima or minima,

V'=0

\implies 100 - 80x + 12x^2 = 0

\implies 3x^2 - 20x + 25=0

By quadratic formula,

x=\frac{20\pm \sqrt{20^2-4\times 3\times 25}}{6}

x=\frac{20\pm \sqrt{400 - 300}}{6}

x=\frac{20\pm \sqrt{100}}{6}

x=\frac{20\pm 10}{6}

\implies x = \frac{10}{6}=\frac{5}{3}\text{ or } x = 5

For x = 5/3, V'' = negative,

While for x = 5, V'' = Positive,

Hence, the value of x would be 5/3 ft for maximising the volume.

8 0
3 years ago
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