Im pretty sure it is the first one
This is called a "substitution problem" is where you have variable that have defined values and plug them in value calculate the expression.
B = 3m + 2p # Starting equation
2 = (3)(5) + 2p # Substitution
2 = 15 + 2p # Multiplication
-13 = 2p # Subtract 15 from both sides
= p # Divide both sides from 2
p =
# Use the reflexive property of equality
Hope this helps!
Answer:
.
Step-by-step explanation:
How many unique combinations are possible in total?
This question takes 5 objects randomly out of a bag of 50 objects. The order in which these objects come out doesn't matter. Therefore, the number of unique choices possible will the sames as the combination
.
How many out of that 2,118,760 combinations will satisfy the request?
Number of ways to choose 2 red candies out a batch of 28:
.
Number of ways to choose 3 green candies out of a batch of 8:
.
However, choosing two red candies out of a batch of 28 red candies does not influence the number of ways of choosing three green candies out of a batch of 8 green candies. The number of ways of choosing 2 red candies and 3 green candies will be the product of the two numbers of ways of choosing
.
The probability that the 5 candies chosen out of the 50 contain 2 red and 3 green will be:
.
Y=6
Reason:
(x,y) -> if 1 is where x is then x=1
-1+7=6