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svp [43]
4 years ago
9

Whoever gets it right and selects all the corret ones gets brainly  also plz help 

Mathematics
1 answer:
Helga [31]4 years ago
8 0
So the large rectangle is a 12x6
the shaded region is 3x3
you can write the proportion as
the top side of the shaded area over the top side of the big rectangle X the left side of the shaded area over the left side of the big rectangle
so
3/12 x 3/6

Hope this helps :)
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Answer:

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3. Uniform A package delivery service breaks up its shipping charges into weight classes, where the package weights are uniforml
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Answer:

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Step-by-step explanation:

An uniform probability is a case of probability in which each outcome is equally as likely.

For this situation, we have a lower limit of the distribution that we call a and an upper limit that we call b.

The probability that we find a value X lower than x is given by the following formula.

P(X \leq x) = \frac{x - a}{b-a}

For this problem, we have that:

a. Suppose one of the shipping classes is 10 to 12 lbs. What proportion of packages in this class would weigh less than 11 lbs?

Uniform distribution from 10 lbs to 12 lbs, this means that a = 10, b = 12.

The answer is P(X \leq 11).

P(X \leq 11) = \frac{11 - 10}{12-10} = 0.5

50% of packages in this class would weigh less than 11 lbs.

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Either a package weighs 11.5 lbs or less, or it weighs more than 11.5 lbs. The sum of the probabilities of these events is decimal 1. So:

P(X \leq 11.5) + P(X > 11.5) = 1

P(X > 11.5) = 1 - P(X \leq 11.5)

P(X > 11.5) = 1 - \frac{11.5-10}{12-10}

P(X > 11.5) = 0.25

25% would weigh more than 11.5 lbs.

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The mean M of the uniform distribution is:

M = \frac{a+b}{2}

So

M = \frac{10+12}{2} = 11

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