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Reil [10]
4 years ago
6

5+19×2 in bodmas formular is what?​

Mathematics
1 answer:
Xelga [282]4 years ago
4 0

Answer:

Step-by-step explanation:

5+19×2

Multiplication come first before addition

= 5 + 18

= 23

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It has been drawing for 3 days
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3 years ago
In △ABC, point M is the midpoint of AB , point D∈ AC so that AD:DC=2:5. If AABC=56 yd2, find ABMC, AAMD, and ACMD.
Komok [63]

Since point M is the midpoint of AB, then AM=MB.

Consider the area of the triangles ABC and BMC:

A_{ABC}=\dfrac{1}{2}\cdot AB\cdot h_c=56\ yd^2,

where h_c is the height drawn from the vertex C to the side AB.

So, AB\cdot h_c=112\ yd^2.

Now

A_{BMC}=\dfrac{1}{2}\cdot BM\cdot h_c=\dfrac{1}{2}\cdot \dfrac{AB}{2}\cdot h_c=\dfrac{1}{4}\cdot AB\cdot h_c=\dfrac{1}{4}\cdot 112=28\ yd^2.

Also

A_{AMC}=A_{ABC}-A_{BMC}=56-28=28\ yd^2.

Now consider the area of the triangles AMD and CMD. Let h_M be the height drawn from the point M to the side AC.

A_{AMD}=\dfrac{1}{2}\cdot AD\cdot h_M=\dfrac{1}{2}\cdot \dfrac{2AC}{7}\cdot h_M=\dfrac{2}{7}\cdot \left(\dfrac{1}{2}\cdot AC\cdot h_M\right)=\dfrac{2}{7}\cdot A_{AMC}=\dfrac{2}{7}\cdot 28=8\ yd^2.

Therefore,

A_{MDC}=A_{AMC}-A_{AMD}=28-8=20\ yd^2.

Answer: A_{MBC}=28\ yd^2, A_{AMD}=8\ yd^2, A_{MDC}=20\ yd^2.

5 0
3 years ago
Read 2 more answers
What is the answer and working out to 5 x 5/6?
nika2105 [10]
The answer for your question is 4.166666667 thank you for letting me answer your question and you welcome now bye have a great day.
3 0
4 years ago
A store is having a 20% off sale on all merchandise. If Mai buys one item and saves $13, what was the original price of her purc
Nadusha1986 [10]

Answer:

Step-by-step explanation:

If a store is having a 20% off sale

By buying an item you save 20% of the price

If Mai saves $13 on an item she is also saving 20%

$13 = 20% of the price

$65 = 100% of the original price

$65 is your answer!

5 0
3 years ago
Read 2 more answers
ALGEBRA 1, SEMESTER 2- please help, im failing my class already
Maru [420]

Velocity is given as 80 feet per second, so replace V with 80.

The rocket is launched from the ground so the initial height is 0, so replace h with 0


The formula now becomes" h(t) = -16t^2 + 80t +0


To find the maximum we need to find the coordinates of the vertex by finding the axis of symmetry:

-b/2a = -80/(2*-16) = -80/-32 = 2.5

This represents the amount of time for the rocket to reach maximum height.

So we now replace t in the equation with 2.5 and solve for the height:

h(2.5) = -16(2.5)^2 + 80(2.5)

h(2.5) = 100


The maximum height is 100 feet

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3 years ago
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