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3 years ago

Dan had 7 dimes in his bank his dad gave him 9 more dimes how many dimes does Dan have now

Mathematics

1 answer:

timofeeve [1]3 years ago

3 0

Answer:

16 dimes

Step-by-step explanation:

He already has 7, and got 9 more, so we can add 7 and 9

7+9 =16

So, Dan has 16 dimes now

Hope this helps! :)

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3 years ago

If a rectangle has side lengths 5x-y and x+4y what would be the area and perimeter of the rectangle?

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Answer:

Answer is given below with explanations. 

Step-by-step explanation:

$given \: \: l = 5x - y \: and \: \: b = x + 4y \\ area \: of \: rectangle \:= l \times b \: sq.units \\ = (5x - y)(x + 4y) \\ = 5 {x}^{2} + 20xy - xy - 4 {y}^{2} \\ = 5 {x}^{2} + 19xy - 4 {y}^{2} \\ perimeter \: of \: rectangle \\ = 2(l + b) \\ = 2(5x - y + x + 4y) \\ = 2(6x + 3y) \\ = 12x + 6y$

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6 0

3 years ago

Need Help Badly What is the solution

Kamila [148]

Sqrt(1-3x)=x+3
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Sorry that this took forever to answer. I was thinking of a good way to explain this, and if you need any further explanation, message me:)

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3 years ago

The length of a rectangle is 7 more than the width. The area is 744 sqaure yards, find the length and width of the rectangle

AVprozaik [17]

Answer:

Length of rectangle is 31 yards and Width is 24 yards.

Given:

The length of a rectangle is 7 more than the width.
The area is 744 sqaure yards

Solution:

Let's assume Width of rectangle be x and Length of rectangle be x + 7 respectively.

Using formula

$\\ \: \: \: \: \pink{ \dashrightarrow \: \: \: \: \sf { \underbrace{Area_{(Rectangle)} = Length × Width }}} \\ \\$

On Substituting the required values, we get;

$\\ \: \: \: \: \dashrightarrow \: \: \: \: \sf (x)(x + 7) = 744 \\ \\ \\ \: \: \: \: \dashrightarrow \: \: \: \: \sf {x}^{2} + 7x = 744 \\ \\ \\ \: \: \: \: \dashrightarrow \: \: \: \: \sf {x}^{2} + 7x - 744 = 0 \\ \\ \\ \: \: \: \: \dashrightarrow \: \: \: \: \sf {x}^{2} + 31x - 24x - 744 = 0 \\ \\ \\ \: \: \: \: \dashrightarrow \: \: \: \: \sf x(x + 31) - 24 (x + 31) = 0 \\ \\ \\ \: \: \: \: \dashrightarrow \: \: \: \: \sf (x + 31)(x - 24) = 0 \\ \\ \\ \: \: \: \: \dashrightarrow \: \: \: \: \sf x = 24 \: or \: - 31 \\ \\$

As we know that width of the rectangle can't be negative. So x = 24

Hence,

Width of rectangle = x = 24 yards
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$\therefore$ Length of rectangle is 31 yards and Width is 24 yards.

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2 years ago