All categories

3 years ago

Is 1/8 bigger or smaller than 3/4?

Mathematics

2 answers:

Advocard [28]3 years ago

5 0

Small, because 1 divided by 8 = 0.125, and 3 divided by 4 = .75 Hope this helps!

Eduardwww [97]3 years ago

5 0

Hello! First, we need to find a common denominator. Let's use 8. The fractions are 1/8 and 6/8 (formerly 3/4). 6/8 is larger than 1/8, therefore 3/4 is greater than 1/8. I hope this helped! Feel free to rate my answer!

You might be interested in

The graph of a polynomial function is shown here.

mezya [45]

Answer:

a i thike mybe

Step-by-step explanation:

3 0

3 years ago

EXPERT HELP I'LL GIVE BRAINLIEST:

Kipish [7]

The answer is a! i hope this helps you!

8 0

3 years ago

Read 2 more answers

In the complex number system, which of the following is equal to

pogonyaev

Answer:

C) $122+154i$

Step-by-step explanation:

$(14-2i)(7+12i)\\\\(14)(7)+(14)(12i)+(-2i)(7)+(-2i)(12i)\\\\98+168i-14i-24i^2\\\\98+154i-24(-1)\\\\98+154i+24\\\\122+154i$

Therefore, C is correct. Recall that $i^2=-1$

3 0

2 years ago

Read 2 more answers

The midpoint of CD is M(-1,-2). One endpoint is C (-9,-4). Find the coordinates of the other endpoint D.

yan [13]

$\bf ~~~~~~~~~~~~\textit{middle point of 2 points }\\\\
\begin{array}{ccccccccc}
&&x_1&&y_1&&x_2&&y_2\\
% (a,b)
&C&(~ -9 &,& -4~) 
% (c,d)
&D&(~ x &,& y~)
\end{array}\qquad
% coordinates of midpoint 
\left(\cfrac{ x_2 + x_1}{2}\quad ,\quad \cfrac{ y_2 + y_1}{2} \right)
\\\\\\
\left( \cfrac{x-9}{2}~~,~~\cfrac{y-4}{2} \right)=\stackrel{midpoint~M}{(-1~~,~~-2)}\implies 
\begin{cases}
\cfrac{x-9}{2}=-1\\\\
x-9=-2\\
\boxed{x=7}\\
----------\\
\cfrac{y-4}{2}=-2\\\\
y-4=-4\\
\boxed{y=0}
\end{cases}$

6 0

3 years ago

Determine the horizontal, vertical, and slant asymptotes: y=x2+2x-3/x-7

densk [106]

Answer:

vertical asymptote: x = 7
slant asymptote: y = x+9

Step-by-step explanation:

The vertical asymptotes are found where a denominator factor is zero (and there is no corresponding numerator factor to cancel it). Here, that is at x = 7.

There is no horizontal asymptote because the numerator is of higher degree than the denominator.

When you divide the numerator by the denominator, you get ...

y = (x +9) +60/(x -7)

Then when x gets large, the behavior is governed by the terms not having a denominator: y = x +9. This is the equation of the slant asymptote.

3 0

3 years ago