Question

A glass pitcher is filled with water. 1/8 of the water is poured equally into 2 glasses.

Answer 1

Answer:

Step-by-step explanation:

Part a)

Let the volume of water in glass pitcher be 'V'

Now it is given that 1/8 of water is poured in 2 glasses

Thus the volume of water in each glass is

$V'=\frac{1}{2}\times \frac{V}{8}=\frac{V}{16}$

Part b)

Now it is given that volume of water in each glass is 3 fluid ounces thus to obtain the original volume we euate the volume obtained in part a with 3. Thus

$\frac{V}{16}=3\\\\\therefore V=3\times 16=48ounces$

Part c)

After pouring out 1/8 water from the orifinal glass the volume of watre that remains in the pitcher euals

$V_{rem}=V-\frac{V}{8}=\frac{7V}{8}$

Now since 1/4 of the above volume is poured out which euals

$V_{poured}=\frac{1}{4}\times \frac{7V}{8}=\frac{7V}{32}$

Thus the volume of water that remains euals

$V'_{rem}=\frac{7V}{8}-\frac{7V}{32}=\frac{21V}{32}$

Applying the value of V we get

$V'_{rem}=\frac{21\times 48}{32}=31.5$ounces