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g100num [7]
4 years ago
10

Please help me i need to find the frequency

Mathematics
1 answer:
kobusy [5.1K]4 years ago
3 0
The frequency for this problem would me x2 every time you add on to the chart or go down the chart good luck:)
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Please help math !!!!!!
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I think it’s the second choice
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4 years ago
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A student in a statistics class asks students in a long lunch line about their opinions about the school cafeteria. The sample t
Paladinen [302]

Answer:

The correct option is;

D. Biased

Step-by-step explanation:

A sampling method in which the members of the sample are not representative of the population, such that some members of the population have a higher or lower probability within the sample which is indicative that not all members of the population are sampled

A biased sample is a non random sample and the can lead to misleading data conclusion

In the question, the sampling of student opinion about the school cafeteria among students who are on the lunch line and so prefer the school cafeteria leaves out the portion of the population that get their lunch from alternative sources.

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3 years ago
Consider the circles A, B, C, and D. SOMEONE PLEASE HELP ASAPPPP THANKS!!!
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Answer:

a= d and b= b

Step-by-step explanation:

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3 years ago
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Determine the mass of a solid steel ball that has a diameter of 10 cm. The density of pure steel is 8.09 g/cm3
Basile [38]

Answer:

<em>The mass of the steel ball is 4,235.9 gr</em>

Step-by-step explanation:

<u>Density</u>

The density ρ of a substance is a measure of its mass per unit volume:

\displaystyle \rho=\frac{m}{V}

If the density and the volume are given, the mass can be calculated by solving the above formula for m:

m=\rho.V

We know the density of pure steel ρ=8.09 gr/cm3 and the diameter of a solid steel ball d=10 cm.

We need to calculate the volume of the sphere:

The volume of a sphere of radius r is given by:

\displaystyle V=\frac{4}{3}\cdot \pi\cdot r^3

The radius is half the diameter: r= 10/2 = 5 cm. Thus:

\displaystyle V=\frac{4}{3}\cdot \pi\cdot 5^3

Calculating:

V=523.6\ cm^3

The mass is:

m=8.09 gr/cm^3 \cdot 523.6\ cm^3

m=4,235.9 gr

The mass of the steel ball is 4,235.9 gr

4 0
3 years ago
What is 3/9 eqvailent to?
svetlana [45]
Answer to question us 1/3
5 0
3 years ago
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