If you expand the square, you have
![\dfrac{1}{4}x^2-3x=7x+8-10x](https://tex.z-dn.net/?f=%5Cdfrac%7B1%7D%7B4%7Dx%5E2-3x%3D7x%2B8-10x)
Simplify the right hand side:
![\dfrac{1}{4}x^2-3x=-3x+8](https://tex.z-dn.net/?f=%5Cdfrac%7B1%7D%7B4%7Dx%5E2-3x%3D-3x%2B8)
Cancel the -3x appearing on both sides:
![\dfrac{1}{4}x^2=8](https://tex.z-dn.net/?f=%5Cdfrac%7B1%7D%7B4%7Dx%5E2%3D8)
Multiply both sides by 4:
![x^2=32](https://tex.z-dn.net/?f=x%5E2%3D32)
Consider the square root of both terms (using the doubles sign):
![x=\pm\sqrt{32}=\pm4\sqrt{2}](https://tex.z-dn.net/?f=x%3D%5Cpm%5Csqrt%7B32%7D%3D%5Cpm4%5Csqrt%7B2%7D)
Answer:
(-5,-3)
Step-by-step explanation:
y values minus y values over x values minus x values
55% of 20 is 11. the answer is 20
6x plus 3x plus 4 minus 2
Answer:
no
Step-by-step explanation: