The Laplace transform of the given initial-value problem
is mathematically given as
<h3>What is the Laplace transform of the given initial-value problem? y' 5y = e4t, y(0) = 2?</h3>
Generally, the equation for the problem is mathematically given as
In conclusion, Taking inverse Laplace tranoform
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Lol just did that myself XD
Rewrite to (6/3) * (10^7/10^4)
(the division of same base numbers with exponents is subtraction of exponents)
so
2 * 10^3
Hope this helps :)
If this helps. 2 x 1= 2 then add the two zeroes since there is two zeroes so your answer is 200
Answer:
10.55 is the answer
Step-by-step explanation:
7.2 + 6.5/2
=> 7.2 + 3.25
=> 10.55
Hope this helps! :3
plz mark as brainliest!
. So there are 4 cups in a quart. So multiply 2 3/4 quarts by 4 to get
(2 3/4) * 4 =
(11/4) * 4 =
11 cups