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Ede4ka [16]
3 years ago
15

Help me i nedd help...........

Mathematics
1 answer:
VMariaS [17]3 years ago
4 0

Answer:

The answer is 10 12/85    Hope you pass!

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What is the general form of the equation for the given circle? A. x2 + y2 − 8x − 8y + 23 = 0 B. x2 + y2 − 8x − 8y + 32 = 0 C. x2
raketka [301]

Answer:

The correct option is A....

Step-by-step explanation:

Look at the attached picture:

A=(4,7)

B=(7,4)

The standard form of circle equation is:

(x-h)^2 +(y-k)^2 = r^2

Here h and k is the centre which is (4,4)

radius = 7-4 = 3

Now use the formula to find the answer:

(x-h)^2 +(y-k)^2 = r^2

(x - 4)^2 + (y - 4)^2 = 3^2

If we expand the formula we get:

x^2 - 8x + 16 + y^2 - 8y + 16 = 9

x^2 - 8x + y^2 - 8y + 23 = 0

Thus the correct option is A....

8 0
3 years ago
2. Suppose that P(A) = 0.32, P(B) = 0.46, P(C) = 0.23, P(A ∪ B) = 0.57, P(A ∪ C) = 0.55, P(B ∪ C) = 0.49. a. Compute P(B ′ ). b.
Liula [17]

Answer:

Step-by-step explanation:

From the given information:

a.

Compute P(B'):

P(B') = 1 - P(B) \\ \\P(B') = 1 - 0.46 \\ \\ P(B') = \mathbf{0.54}

b.

Compute P(A ∩ B)

P(A ∩ B) =  P(A) +P(B) - P(A∪B)

P(A ∩ B) =  0.32 + 0.46 - 0.57

P(A ∩ B) =  0.21

Thus, since P(A ∩ B) ≠ 0, we can say that they are not mutually exclusive.

c.

P(A ∩ C) = P(A) +P(C) - P(A∪C)

P(A ∩ C) = 0.32 + 0.23 -0.55

P(A ∩ C) =  0

Thus, since P(A ∩ C) = 0, we can say that they are both mutually exclusive.

d. To determine  P[(A ∪ B ∪ C)′]

i.e. none of the events occurring

Then :

P(B ∩ C) = 0.46 +0.23 -0.49

P(B ∩ C) = 0.20

Therefore:

P(A ∪ B ∪ C) = P(A) + P(B) + P(C) - P(A ∩ B ) - P(A  ∩ C) - P(B ∩ C)  + P(A ∩ B ∩ C)

P(A ∪ B ∪ C) = 0.32 + 0.46 + 0.23 - 0.21 - 0 - 0.20 + 0

P(A ∪ B ∪ C) = 0.60

3 0
3 years ago
Please help I'am lost on these two thank you
azamat
The first one is D. (2+11)7=7(2+11)
I'm not sure of the second one, I apologize.
4 0
3 years ago
Read 2 more answers
Do two points always, sometimes, or never determine a line? Explain.
mel-nik [20]

Answer: sometimes

explanation:

if there are two points then there could be a line to connect them, however, there could always be two points that are separate on their own.

8 0
3 years ago
Read 2 more answers
How do you make .208 a fraction?
seropon [69]
0.\underbrace{208}_{3}=\frac{208}{1\underbrace{000}_3}=\frac{208}{1000}\\\\divide\ a\ numerator\ and\ a\ denominator\ by\ 8\\\\\frac{208}{1000}=\frac{26}{125}\\\\Answer:0.208=\frac{26}{125}
6 0
4 years ago
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