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Natalka [10]
3 years ago
5

Solve fast if you solve that I will give you brainly.

Mathematics
1 answer:
serg [7]3 years ago
3 0

Answer: 150m

Step-by-step explanation:

If mr A beats mr B by 70

and mr B beats Mr C by 80

you add up the 2 values and get 150

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Can a three liter go in a half gallon
Shtirlitz [24]
Yes. Three liters is equal to 0.792516 of a gallon
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A caterer prepared a turkey that weighed 27 1/2 pounds. Each serving of turkey will be 1/3 pound. How many whole servings will t
Kaylis [27]

Answer:

82.5000001 Close to around this ( maybe .11 off)

Explanation:

27.5 ÷ .33333333 = 82.5000001

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What’s the anwers ? Need help
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5 because 2/6 of 24 is 8 and the difference of thirteen and 8 is 5
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A (5, 3), B (2, 1), and C (-2, 4) are the coordinates of a triangle's vertices. If the triangle is reflected over the x -axis, w
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3 not the right anwser

Step-by-step explanation:


8 0
3 years ago
On Texas Avenue between University Drive and George Bush Drive, accidents occur according to a Poisson process at a rate of thre
Zarrin [17]

Answer:

(a) The probability is 0.6514

(b) The probability is 0.7769

Step-by-step explanation:

If the number of accidents occur according to a poisson process, the probability that x accidents occurs on a given day is:

P(x)=\frac{e^{-at}*(at)^{x} }{x!}

Where a is the mean number of accidents per day and t is the number of days.

So, for part (a), a is equal to 3/7 and t is equal to 1 day, because there is a rate of 3 accidents every 7 days.

Then, the probability that a given day has no accidents is calculated as:

P(x)=\frac{e^{-3/7}*(3/7)^{x}}{x!}

P(0)=\frac{e^{-3/7}*(3/7)^{0}}{0!}=0.6514

On the other hand the probability that February has at least one accident with a personal injury is calculated as:

P(x≥1)=1 - P(0)

Where P(0) is calculated as:

P(x)=\frac{e^{-at}*(at)^{x} }{x!}

Where a is equivalent to (3/7)(1/8) because that is the mean number of accidents with personal injury per day, and t is equal to 28 because 4 weeks has 28 days, so:

P(x)=\frac{e^{-(3/7)(1/8)(28)}*((3/7)(1/8)(28))^{x}}{x!}

P(0)=\frac{e^{-(3/7)(1/8)(28)}*((3/7)(1/8)(28))^{0}}{0!}=0.2231

Finally, P(x≥1) is:

P(x≥1) = 1 - 0.2231 = 0.7769

3 0
3 years ago
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