The value of c such that the function f is a probability density function is 2
<h3>How to determine the value of c?</h3>
The density function is given as:
f(x) = cxe^(−x^2) if x ≥ 0
f(x) = 0 if x < 0.
We start by integrating the function f(x)
∫f(x) = 1
This gives
∫ cxe^(−x^2) = 1
Next, we integrate the function using a graphing calculator.
From the graphing calculator, we have:
c/2 * (0 + 1) = 1
Evaluate the sum
c/2 * 1 = 1
Evaluate the product
c/2 = 1
Multiply both sides of the equation by 2
c = 2
Hence, the value of c such that the function f is a probability density function is 2
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A = length x width
So, this would be 4(3)
(I believe that would be it anyway …) ♀️
Answer:
-155
Step-by-step explanation:
Answer:
Step-by-step explanation:
Let the coordinates of d be (x,y)
The midpoint of (x,y) and (-5,-3) is equal to ((-5+x)/2, (-3+y)/2)
this should be equal to the coordinates of e, (-6,4)
we have (-5/2+x/2, -3/2+y/2)
-5/2+x/2 = -6
-5 + x = -12
x = -7
-3/2+y/2 = 4
-3+y = 8
y = 11
Therefore the coordinates of d are (-7,11)
Answer:
4) 7a+20
5) 14+2b
6) 25c² - 15
Step-by-step explanation:
4) 9a+7-2a+13= 9a-2a+7+13 = 7a+20
5) 21-3b+5b-7= 21-7+5b-3b = 14+2b
6) (3c)² + (8c)² - 15 = 9c² + 16c² - 15 = 25c² - 15
