What is 15+12x-5x+4y-7 by combining like terms

Mathematics

2 answers:

luda_lava [24]3 years ago

7 0

Answer:

8+7x+4y

Step-by-step explanation:

15-7 is 8

12x-5x is 7

Put it all together to get 8+7x+4y

cricket20 [7]3 years ago

6 0

Answer:

4y+7x+8

Step-by-step explanation:

First you combine any terms with y. There is only 4y so you write that down. Then, you combine the terms with x. 12x-5x=7x. Then, you combine the regular numbers so you get 8. Your final answer should be 4y+7x+8

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Help please this is for inequality math!! n + 7 < - 3

stealth61 [152]

Answer:

n < -10

Step-by-step explanation:

n+7 < -3

subtract 7 from both sides

n+7-7 < -3-7

n < -10

4 0

2 years ago

You have a six-sided die that you roll once. Let Ri denote the event that the roll is i. Let G j denote the event that the roll

Misha Larkins [42]

Answer:

a. $P (R3 | G1)=\frac{1}{5}$

b. $P (R6| G3)= \frac{1}{3}$

c. $P(G3|E)=\frac{2}{3}$

d. $P (E|G3)=\frac{2}{3}$

Step-by-step explanation:

The sample space associated with the random experiment of throwing a dice is is the equiprobable space {R1, R2, R3, R4, R5, R6}. Then,

a. The conditional probability that 3 is rolled given that the roll is greater than 1? $P (R3 | G1) = \frac{P (R3\bigcap G1)}{P(G1)} = \frac{1/6}{5/6} = \frac{1}{5}$

b. What is the conditional probability that 6 is rolled given that the roll is greater than 3? $P (R6| G3) = \frac{P (R6\bigcap G3)}{P(G3)} = \frac{1/6}{3/6} = \frac{1}{3}$

c. What is P [GIE], the conditional probability that the roll is greater than 3 given that the roll is even? $P(G3|E) = \frac{P (G3\bigcap E)}{P(E)} = \frac{2/6}{3/6} = \frac{2}{3}$

d. Given that the roll is greater than 3, what is the conditional probability that the roll is even? $P (E|G3) = \frac{P (E\bigcap G3)}{P(G3)} = \frac{2/6}{3/6} = \frac{2}{3}$