Given:
Point F,G,H are midpoints of the sides of the triangle CDE.

To find:
The perimeter of the triangle CDE.
Solution:
According to the triangle mid-segment theorem, the length of the mid-segment of a triangle is always half of the base of the triangle.
FG is mid-segment and DE is base. So, by using triangle mid-segment theorem, we get




GH is mid-segment and CE is base. So, by using triangle mid-segment theorem, we get




Now, the perimeter of the triangle CDE is:



Therefore, the perimeter of the triangle CDE is 56 units.
B involves direct variation.
y and x are directly proportional.
Answer:
Step-by-step explanation:
Given function is,
f(x) = 
If the given function is vertically stretched by a scale factor of
Or 1.5,
Transformed function will be,
h(x) = ![\frac{3}{2}[f(x)]](https://tex.z-dn.net/?f=%5Cfrac%7B3%7D%7B2%7D%5Bf%28x%29%5D)
h(x) = 
Further function 'h' is shifted 1 units upwards,
g(x) = h(x) + 1
g(x) = 
Domain of the function → x ≥ 0 Or [0, ∞)
Range of the function → y ≥ 1 Or [1, ∞)
Transformations done → Parent function f(x) is vertically stretched by a scale factor of
then shifted 1 unit upward.