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uysha [10]
4 years ago
14

A coffee shop plans to blend a coffee that sells for $12 per pound with coffee that sells for $9 per pound to produce a blend th

at sells for $10 per pound. How much of each should be used to produce 20 pounds of the new blend?
Mathematics
1 answer:
zvonat [6]4 years ago
8 0

Answer:

20/3 pounds of coffee that costs $12 per pound  and 40/3 pounds  of coffee that costs $9 per pound are required

Step-by-step explanation:

Let x be the amount of coffee that costs $12 per pound

Cost of x amount of this type coffee = 12x

We are supposed to find How much of each should be used to produce 20 pounds of the new blend that costs $10 per pound

So, Amount of coffee required that costs $9 per pound = 20-x

Cost of (20-x) amount of this type of coffee = 9(20-x)

So, 12x+9(20-x)=10(20)\\12x+180-9x=200\\3x=20\\x=\frac{20}{3}

Amount of coffee that costs $12 per pound required is\frac{20}{3} pounds

Amount of coffee that costs $9 per pound required = 20-x=20-\frac{20}{3}=\frac{40}{3} pounds

Hence 20/3 pounds of coffee that costs $12 per pound  and 40/3 pounds  of coffee that costs $9 per pound are required

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Answer:

The correct answer is third option

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Step-by-step explanation:

From the figure we can see a right angled triangle ABC.

Right angled at C.

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<u>Points to remember</u>

Tan θ = Opposite side/Adjacent side

<u>To find the value of tan(B)</u>

Tan B =  Opposite side/Adjacent side

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Therefore the value of tan(B) =  1/√3

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Solve this for me (geometry)
VashaNatasha [74]

Given:

A figure of a circle. KJ=6,KL=x-2,ML=4.

To find:

The length of KJ.

Solution:

From the given figure it is clear that the number 6 is marked between K and J it means the number 6 represents the distance between the points K and j.

Therefore, the length of KJ is 6 units.

Note: In the given question we need to find KL instead of KJ because KJ is already given.

According to the tangent secant theorem:

a^2=bc

Where,

  • a is the length of the tangent.
  • b is the length of the external segment of the secant.
  • c is the measure of the secant.

Using the tangent secant theorem, we get

ML^2=KL\times JL

(4)^2=(x-2)\times (6+x-2)

16=(x-2)\times (4+x)

16=4x+x^2-8-2x

On further simplification, we get

16=x^2+2x-8

0=x^2+2x-8-16

0=x^2+2x-24

Splitting the middle term, we get

x^2+6x-4x-24=0

x(x+6)-4(x+6)=0

(x+6)(x-4)=0

x=-6,4

For x=-6,

KJ=-6-2

KJ=-8, which is not possible because side cannot be negative.

For x=4,

KJ=4-2

KJ=2

Therefore, the measure of KL is 2 units.

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3 years ago
Complete the statement, then write the postulate you used.
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The answer is MN with a bar/line on top of it
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