<span>We have lateral faces that are rectangles and 2 congruent polygons that are bases. This must be 3-dimensional solid figure - quadrilateral prism. If those 2 bases are squares then it is a rectangular prism, but the bases also can be 2 rhombuses. Answer: Quadrilateral prism.</span><span />
Answer:
ok so first we need to find the area of the circle inside which is a=Pi*raduis^2
a=pi*1(radius is half of diamater)
a=3.14
ok then the area of the sqare including the circle is 16 so
16-3.14=12.86
this is is aprox since the area of pi is infinite and i just used 3.14
Hope This Helps!!!
Answer:
lw + 
× π × 
⇒ Answer D is correct
Step-by-step explanation:
First, let us find the area of the semi-circle.
Area = × π × r²
<u>Given that,</u>
diameter of the semi-circle is ⇒ <em>l</em>
∴ radius ⇒ <em>l / 2</em>
<u>Let us find it now.</u>
Area = × π × r²
Area = × π ×
<u> </u>
Secondly, let us find the area of the rectangle.
Area = length × width
<u>Given that,</u>
length ⇒ <em>l</em>
width ⇒ w
<u>Let us find it now.</u>
Area = length × width
Area = l ×w
Area = lw
<u> </u>
And now let us <u>find the total area.</u>
Total area = Area of the rectangle + Area of the semi - circle
Tota area = lw + × π ×
Answer:
z=5
Step-by-step explanation:
12.2z+ 19.4 = -2.7z + 93.9
14.9z=74.5
z=5
Step-by-step explanation:
In words it is: The product of -11 and k is 22.
The solution is: -11 = +11
22+11 = 33
33 = k
