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vampirchik [111]
3 years ago
7

What is 15% added to $185.30

Mathematics
1 answer:
Ilia_Sergeevich [38]3 years ago
5 0

Answer:

$213.095

Step-by-step explanation:

15% of 185.30 = 185.30/100*15 = 27.795

So to find what is 15% added to 185.50, we use 185.30 + 27.795 = $213.095

Hope this help :3

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Explain how you can write a quadratic function in a factored form that would have a vertex with an x-coordinate of 3 and two dis
Elena-2011 [213]

Answer:

Step-by-step explanation:

(x-3)²-4=0

(x-3)²=4=2²

x-3=±2

x=3±2

x=3-2,3+2

x=1,5

it has two distinct roots and a vertex at x=3

3 0
2 years ago
A football is thrown from the top of the stands, 50 feet above the ground at an initial velocity of 62 ft/sec and at an angle of
Anvisha [2.4K]

a. i. The parametric equation for the horizontal movement is x = 43.84t

ii. The parametric equation for the vertical movement is y = 50 + 43.84t

b. the location of the football at its maximum height relative to the starting point is (60.1 ft, 60.1 ft)

<h2>a. Parametric equations</h2>

A parametric equation is an equation that defines a set of quantities a functions of one or more independent variables called parameters.

<h3>i. Parametric equation for the horizontal movement</h3>

The parametric equation for the horizontal movement is x = 43.84t

Since

  • the angle of elevation is Ф = 45° and
  • the initial velocity, v = 62 ft/s,

the horizontal component of the velocity is v' = vcosФ.

So, the horizontal distance the football moves in time, t is x = vcosФt

= vtcosФ

= 62tcos45°

= 62t × 0.7071

= 43.84t

So, the parametric equation for the horizontal movement is x = 43.84t

<h3>ii Parametric equation for the vertical movement</h3>

The parametric equation for the vertical movement is y = 50 + 43.84t

Also, since

  • the angle of elevation is Ф = 45° and
  • the initial velocity, v = 62 ft/s,

the vertical component of the velocity is v" = vsinФ.

Since the football is initially at a height of h = 50 feet, the vertical distance the football moves in time, t relative to the ground is y = 50 + vsinФt

= 50 + vtcosФ

= 50 + 62tsin45°

= 50 + 62t × 0.7071

= 50 + 43.84t

<h3>b. Location of football at maximum height relative to starting point</h3>

The location of the football at its maximum height relative to the starting point is (60.1 ft, 60.1 ft)

Since the football reaches maximum height at t = 1.37 s

The x coordinate of its location at maximum height is gotten by substituting t = 1.37 into x = 48.84t

So, x = 43.84t

x = 43.84 × 1.37

x = 60.0608

x ≅ 60.1 ft

The y coordinate of the football's location at maximum height relative to the ground is y = 50 + 48.84t

The y coordinate of the football's location at maximum height relative to the starting point is y - 50 = 48.84t

So,  y - 50 = 48.84t

y - 50 = 43.84 × 1.37

y - 50 = 60.0608

y - 50 ≅ 60.1 ft

So, the location of the football at its maximum height relative to the starting point is (60.1 ft, 60.1 ft)

Learn ore about parametric equations here:

brainly.com/question/8674159

5 0
2 years ago
A survey found that women's heights are normally distributed with mean 62.8 inches and standard deviation of 2.5 inches. This su
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<span>a) 

Z*_Upper = (76 - 62.7)/2.5 = 5.32

Z*_Lower = (57 - 62.7)/2.5 = -2.28 

The requirement is to get p(-2.28 < Z < 5.32) = p(Z<5.32) - p(Z<-2.28). 

Use normal distribution table to get the answer for p and multiply with 100 to get the percentage. 

The other questions are now easy for you to answer on your own. Hope it helps.

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The rates for a long distance telephone call are $0.70 for the first 5 minutes and $0.40 for each additional minute. How much wo
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$0.56. 0.7/5=$0.14 $0.14 is the amount per minute. so then you would multiply $0.14 x 4= $ 0.56
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The answer is -6x^2 + 7x, or answer choice A.
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