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Cloud [144]
4 years ago
10

Which of the following correctly simplifies the expression 3 to the power of 2 multiplied by 5 to the power of 0 whole over 4, t

he whole squared.? (5 points)
Group of answer choices

3 to the power of 2 multiplied by 1 whole over 4, the whole squared. = 3 to the power of 1 multiplied by 1 squared over 4 squared. = 1 over 6.

3 to the power of 2 multiplied by 0 whole over 4, the whole squared. = 3 to the power of 1 multiplied by 0 over 4 squared. = 0

3 to the power of 2 multiplied by 0 whole over 4, the whole squared. = 3 to the power of 4 multiplied by 0 over 4 squared. = 0

3 to the power of 2 multiplied by 1 whole over 4, the whole squared. = 3 to the power of 4 multiplied by 1 squared over 4 squared. = 81 over 16.
Mathematics
1 answer:
EastWind [94]4 years ago
3 0

Answer: 21

Step-by-step explanation:

9  + 10 = 21

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6 0
4 years ago
Morgan has $60 to spend on clothes. he wants to buy a pair of jeans for $25 and spend the rest on t shirts each t shirt costs $5
Mashutka [201]

Answer:

C

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Morgan has $60. That is his spending limit.

He buys a pair of jeans for $25.

Each T-shirt is $5

We don't know how many t-shirts he can buy, so we can represent it with a variable, x

so,

25 + 5x \leq 60\\5x \leq 60 - 25\\5x \leq 35\\x \leq \frac{35}{5} \\x\leq 7

6 0
3 years ago
a 16 inch wire is to be cut. one piece is to be bent into the shape of a​ square, whereas the other piece is to be bent into the
Lyrx [107]
1. Let x be a length of square side, then the square perimeter is 4x (you need to cut 4x from 16 in. to make a square with side x in.). Then 16-4x is remained length of wire and you have to make form this piece a rectangle with sides one of which is twice bigger than another. If y is length of the smaller side, then 2y is length of the bigger side and rectangle perimeter is y+2y+y+2y=6y. You have 16-4x in. of wire left, so 6y=16-4x and y= \frac{16-4x}{6}.

2.
 A_{square}=x^2 \\ A_{rectangle}=y\cdot 2y=\frac{16-4x}{6}\cdot2\cdot\frac{16-4x}{6}= \frac{(16-4x)^2}{18}  \\ A(x)=A_{square}+A_{rectangle}=x^2+\frac{(16-4x)^2}{18}.

3. Find the derivative of the function A(x): 
A'(x)=2x+ \dfrac{2(16-4x)\cdot(-4)}{18} =2x- \dfrac{4(16-4x )}{9}.

4. Solve the equation A'(x)=0: 
2x- \dfrac{4(16-4x )}{9}=0 \\ 18x-64+16x=0 \\ 34x=64 \\ x= \frac{32}{17}

5. Since y= \frac{16-4x}{6} you have

y= \dfrac{16-4 \frac{32}{17} }{6} = \dfrac{16\cdot17-4\cdot32}{6\cdot 17} = \dfrac{24}{17}.

Answer: <span>the width of the rectangle is \frac{24}{17}</span>




6 0
4 years ago
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