I need help with this

If s denotes the length of the arc of a circle of radius r subtended by a central angle \theta , find the missing quantity.

bulgar [2K]

The correct answer would be D. 2.7 m meters.

To solve this,
v=s/r
since we have s = 7.02 meters, \theta = 2.6
Then
7.02/2.6 = 2.7m

The correct answer is d. 2.7 m. This is the missing quantity which is the radian.

Thank you for posting your question. I hope that this answer helped you. Let me know if you need more help.

6 0

4 years ago

Suppose that the members of a student governance committee will be selected from the 40 members of the student senate. There are

Len [333]

Answer:

The total number of ways to form a student governance committee is 1,211,760.

Step-by-step explanation:

The students senate consists of a total of 40 students.

The students are either Sophomores or Juniors or Seniors.

The number of students in each of these categories are as follows:

Sophomores = 18

Juniors = 12

Seniors = 10

A governance committee have to be selected from the students senate.

The committee have to made up of 2 sophomores, 2 juniors and 3 seniors.

Combinations can be used to select 2 sophomores from 18, 2 juniors from 12 and 3 seniors from 10.

Combinations is a mathematical technique used to determine the number of ways to select k items from n distinct items.

The formula is:

${n\choose k}=\frac{n!}{k!(n-k)!}$

(1)

Compute the number of ways to select 2 sophomores from 18 as follows:

${n\choose k}=\frac{n!}{k!(n-k)!}$

${18\choose 2}=\frac{18!}{2!(18-2)!}=\frac{18\times 17\times 16!}{2\times 16!}=153$

Thus, there are 153 ways to select 2 sophomores from 18.

(2)

Compute the number of ways to select 2 juniors from 12 as follows:

${n\choose k}=\frac{n!}{k!(n-k)!}$

${12\choose 2}=\frac{12!}{2!(12-2)!}=\frac{12\times 11\times 10!}{2\times 10!}=66$

Thus, there are 66 ways to select 2 juniors from 12.

(3)

Compute the number of ways to select 3 seniors from 10 as follows:

${n\choose k}=\frac{n!}{k!(n-k)!}$

${10\choose 3}=\frac{10!}{3!(10-3)!}=\frac{10\times 9\times 8\times 7!}{2\times 3\times 7!}=120$

Thus, there are 120 ways to select 3 seniors from 10.

The total number of ways to form a student governance committee that must have 2 sophomores, 2 juniors and 3 seniors is:

Total number of ways = ${18\choose 2}\times {12\choose 2}\times {10\choose 3}$

$=153\times 66\times 120\\=1211760$

Thus, the total number of ways to form a student governance committee is 1,211,760.

7 0

3 years ago

the perimeter of a triangle is 75 cm. The triangle is isosles now, but if its base were lenghthened by 2 cm and each leg were sh

OLEGan [10]

(-14)+2=(-12)

75-12=63

63/3=21

21-2=19 BASE=19

21+7=28 EACH LEG=28

28+28+19=75

new triangle 21+21+21

19+2=21

28-7=21

4 0

4 years ago

5 of 12

AnnZ [28]

Answer: The Cars Average Speed Will Be 60Mph.

4 0

3 years ago

HELP ME WITH THIS QUESTION PLEASE!!!!!

Lynna [10]

The image won’t load. can you send me the question through the comments?

7 0

3 years ago