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Alenkinab [10]
3 years ago
6

Consider the following short paragraph: On a computer with a single core CPU, attempting to program real concurrency between two

processes (as opposed to apparent concurrency) is impossible, because the CPU can in actuality only do one thing at a time. To fake the user into thinking that more than one process is running at the same time, the CPU can, for example, switch back and forth between running each process very quickly. Choose one of the following statements about this paragraph: Group of answer choices It is all true It is all false Some of it is true, and some of it is false
Computers and Technology
1 answer:
fgiga [73]3 years ago
7 0

Answer:

It is all true.

Explanation:

All the statements of the paragraph are true.  

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4 years ago
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andreyandreev [35.5K]

Answer:

<h2>1)   </h2>

h = 19  # h is already assigned a positive integer value 19

i = 1  # used to calculate perfect square

q = 0   # stores the sum of the perfect squares

while q < h:  

# this loop executes until value of number of perfect squares is less than h

   q = q + (i*i)  # to calculate the sum of perfect squares

   i = i + 1  # increments i by 1 at every iteration

print(q) # displays the sum of perfect squares

Output:

30

Explanation:

Here we see that the sum of the perfect square is printed in the output i.e. 30. If we want to assign value 4 to q then we should alter the code as  following:  

h = 19

i = 1

sum_of_ps = 0

q=0

while sum_of_ps < h:

   sum_of_ps = sum_of_ps + (i*i)

   q = q + 1

   i = i + 1  

print(q)  

If you want to take input from the user and also display the perfect squares in output you can use the following code:

h = int(input('Enter the value of h: ')) #takes value of h from user

i = 1

sum_of_ps = 0

q=0

while sum_of_ps < h:

   sum_of_ps = sum_of_ps + (i*i)

   print(i*i) #displays the perfect squares of h

   q = q + 1

   i = i + 1    

print(sum_of_ps)   #displays sum of perfect squares

print(q) #displays number of perfect squares whose value is less than h

Output:

1

4

9

16

30

4

<h2>2)</h2>

# k and m are already assigned positive integers 10 and 40

k = 10  

m = 40  

i = 1  # i is initialized to 1

q = 0  # q stores the number of perfect squares between k and m

while i*i < m:  # loop computes perfect square of numbers between k and m

   if i*i > k:          

       q = q + 1  # counts the number of perfect squares

   i = i + 1  #increments the value of i at each iteration

print (q) # prints the no of perfect squares between k and m

If you want to display the perfect squares too use , add print(i*i) statement after if statement  if i*i > k:        

Output:

3

<h2>3)</h2>

def Fibonacci(n):  # method Fibonacci which has an integer parameter n

   if n <= 1:  # if the value of n is less than or equals to 1

       result = n  # stores the value of n into result

   elif n > 1:  # else if the value of n is greater than 1

       result = Fibonacci(n-1) + Fibonacci(n-2)  

# calls Fibonacci method recursively to associate nth value of Fibonacci #sequence with variable result

   return result     #returns the final value stored in result variable

print(Fibonacci(8))

#calls Fibonacci function and passes value 8 to it

Output:

21

8 0
3 years ago
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