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Usimov [2.4K]
3 years ago
13

Circle O has a circumference of approximately 44 in.

Mathematics
2 answers:
ICE Princess25 [194]3 years ago
6 0

Answer:44

Step-by-step explanation:

Vesnalui [34]3 years ago
4 0
The correct answer is: 14 in ..
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Please help me guys!!!:)
mash [69]

Answer:

The answer is >

second one

Step-by-step explanation:

Good luck !

6 0
3 years ago
Tals, we werest Deus
lisov135 [29]

Answer:

The time will be "3 years".

Step-by-step explanation:

The given values are:

Principle,

P = 5120

Amount,

A = 7290

Rate,

r = 12.5

Time,

n = ?

As we know,

⇒  A = P[1+\frac{r}{100} ]n

On substituting the values, we get

⇒  7290=5120[1+\frac{12.5}{100} ]n

On applying cross-multiplication, we get

⇒  \frac{7290}{5120}=[1+\frac{125}{100}\times 100 ]n

⇒  \frac{9}{8}\times 3=[8+\frac{1}{8} ]n

⇒  n = 3 \ years    

8 0
3 years ago
Simplify the expression -|-13|
Afina-wow [57]

Answer:

-13

Step-by-step explanation:

plz mark me as brainliest

4 0
3 years ago
Read 2 more answers
Kari needs to make copies of a horse show . the printer can make 24 in 1 minute . Kari says the printer can make 114 in 6 minute
pogonyaev
No, Kari is not correct. 24 times 6 does not equal 114, it equals 144.
7 0
3 years ago
Read 2 more answers
A student club holds a meeting. The predicate M(x) denotes whether person x came to the meeting on time. The predicate O(x) refe
Novay_Z [31]

Answer:

a) \exists \, x \in C : O(x) = 0

b) \{ x \in C : O(x) = 1 \} \subseteq \{ x \in C : M(x) = 1 \}

c) \{ x \in C: M(x) = 1 \} = C

d) \{ x \in C : D(x) = 1 \} \, \cup \, \{x \in C : M(x) = 1 \} = C

e) \exists \, x \in C : M(x) = 1 \, \wedge D(x) = 1

f) \exists \, x \in C : O(x) = 1 \, \wedge M(x) = 0

Step-by-step explanation:

  • M(x) = 1 if the person x came to the meeting, and 0 otherwise.
  • O(x) = 1 if the person is an officer of the club and 0 otherwise.
  • D(x) = 1 if the person has paid hid/her club dues and 0 otherwise.

Lets also call C the set given by the members of the club. C is the domain of the functions M, O and D.

a) If someone is not an officer, the there should be at least one value x such that O(x) = 0. This can be expressed by logic expressions this way

\exists \, x \in C : O(x) = 0

b) If all the officers came on time to the meeting, then for a value x such that O(x) = 1, we also have that M(x) = 1. Thus, the set of officers of the Club is contained on the set of persons which came to the meeting on time, this can be written mathematically this way:

\{ x \in C : O(x) = 1 \} \subseteq \{ x \in C : M(x) = 1 \}

c) If everyone was in time for the meeting, then C is equal to the set of persons who came to the meeting on time, or, equivalently, the values x such that M(x) = 1. We can write that this way:

\{ x \in C: M(x) = 1 \} = C

d) If everyone paid their dues or came on time to the meeting, then if we take the set of persons who came to the meeting on time and the set of the persons who paid their dues, then the union of the two sets should be the entire domain C, because otherwise there should be a person that didnt pay nor was it on time. This can be expressed logically this way:

\{ x \in C : D(x) = 1 \} \, \cup \, \{x \in C : M(x) = 1 \} = C

e) If at least one person paid their dues on time and came on time to the meeting, then there should be a value x on C such that M(x) and D(x) are both equal to 1. Therefore

\exists \, x \in C : M(x) = 1 \, \wedge D(x) = 1

f) If there is an officer who did not come on time for the meeting, then there should be a value x in C such that O(x) = 1 (x is an officer), and M(x) = 0. As a result, we have

\exists \, x \in C : O(x) = 1 \, \wedge M(x) = 0

I hope that works for you!

7 0
4 years ago
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