Please help me<br><br><br> it is an emergecy if you can help.

Claudia's skis are 150 centimeters long. how many millimeters is this?

alex41 [277]

the answer to this question is 1500 millimeters

6 0

3 years ago

Determine whether the following problem involves a permutation or a combination and explain your answer. How many different -le

Alex_Xolod [135]

Answer:

B. The problem involves a combination because the order in which the letters are selected does not matter.

Step-by-step explanation:

Computation technique is a method of statistics to find possible ways of combination. In computation technique it is assumed that order does not matter and letters will be selected at random. Permutation is a statistics technique to find possible ways of combination when the order does matter. Permutation technique cannot be used when order does not matter.

4 0

3 years ago

A website manager has noticed that during the evening hours, about 3.23.2 people per minute check out from their shopping cart

aleksandrvk [35]

Answer:

1. c. Poisson

2. 0.9592 = 95.92% probability that in any one minute at least one purchase is made.

3. 0.0017 = 0.17% probability that no one makes a purchase in the next 2 minutes.

Step-by-step explanation:

We have only the mean, which means that the Poisson distribution is used to solve this question, and thus the answer to question 1 is given by option c.

Poisson distribution:

In a Poisson distribution, the probability that X represents the number of successes of a random variable is given by the following formula:

$P(X = x) = \frac{e^{-\mu}*\mu^{x}}{(x)!}$

In which

x is the number of sucesses

e = 2.71828 is the Euler number

$\mu$ is the mean in the given interval.

Mean of 3.2 minutes:

This means that $\mu = 3.2n$ , in which n is the number of minutes.

2. What is the probability that in any one minute at least one purchase is made?

$n = 1$ , so $\mu = 3.2$ .

This probability is:

$P(X \geq 1) = 1 - P(X = 0)$

In which

$P(X = x) = \frac{e^{-\mu}*\mu^{x}}{(x)!}$

$P(X = 0) = \frac{e^{-3.2}*3.2^{0}}{(0)!} = 0.0408$

So

$P(X \geq 1) = 1 - P(X = 0) = 1 - 0.0408 = 0.9592$

0.9592 = 95.92% probability that in any one minute at least one purchase is made.

3. What is the probability that no one makes a purchase in the next 2 minutes?

2 minutes, so $n = 2, \mu = 3.2(2) = 6.4$

This probability is P(X = 0). So

$P(X = x) = \frac{e^{-\mu}*\mu^{x}}{(x)!}$

$P(X = 0) = \frac{e^{-6.4}*6.4^{0}}{(0)!} = 0.0017$

0.0017 = 0.17% probability that no one makes a purchase in the next 2 minutes.

7 0

3 years ago

Help!!!!!!!!!!!!!!!!!!!!!!!

murzikaleks [220]

Answer:

A) g = 11

Step-by-step explanation:

26 = 7g - 63 + 12

26 = 7g - 51

77 = 7g

g = 11

7 0

3 years ago

Write the slope-intercept form of the equation of each line.

rewona [7]

Answer:

$y=-\frac{8}{3} x - 3$

Step-by-step explanation:

Slope-intercept form is y = mx + b.

You are given 8x + 3y = -9, so to convert this into slope-intercept form you would solve for y and rearrange the terms (if needed) to follow the format of mx + b.

Start by subtracting 8x from both sides of the equation.

3y = -9 - 8x

Divide both sides by 3 to isolate y.

y = -3 - 8/3x

Rearrange the terms so the "x" variable is first.

y = -8/3x - 3

6 0

3 years ago

Please help me it is an emergecy if you can help.