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Ludmilka [50]
2 years ago
6

$4 is what percent of $50 ? show work

Mathematics
1 answer:
hoa [83]2 years ago
7 0
The answer would be 8 although, if you have to show work I can't help you.. I'm trying to help but I haven't learned percentage yet so I am using my percentage calculator.
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A function is a rule that assigns each value of the __variable to exactly one value of the dependent variable
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Independent

Step-by-step explanation:

Answer: A function is a rule that assigns each value of the independent variable to exactly one value of the dependent variable.

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The antibiotic clarithromycin is eliminated from the body according to the formula A(t) = 500e−0.1386t, where A is the amount re
PolarNik [594]

Answer:

Time(t) = 11.61 hours (Rounded to two decimal place)

Step-by-step explanation:

Given: The antibiotic  clarithromycin is eliminated from the body according to the formula:

A(t) = 500e^{-0.1386t}                 ......[1]

where;

A - Amount remaining in the body(in milligram)

t - time in hours after the drug reaches peak concentration.

Given: Amount of drug in the body is reduced to 100 milligrams.

then,

Substitute the value of A = 100 milligrams in [1] we get;

100= 500e^{-0.1386t}

Divide both sides by 500 we get;

\frac{100}{500}=\frac{ 500e^{-0.1386t}}{500}

Simplify:

\frac{1}{5} = e^{-0.1386t}

Taking logarithm both sides with base e, then we have;

\log_e (\frac{1}{5})= \log_e (e^{-0.1386t})

\log_e (\frac{1}{5})=-0.1386t         [ Using \log_e e^a =a ]

or

\log_e (0.2)=-0.1386t

-1.6094379124341 = -0.1386t

 [using value of \log_e (0.2) = -1.6094379124341 ]

then;

t = \frac{-1.6094379124341}{-0.1386}

Simplify:

t ≈11.61 hours.

Therefore, the time 11.61 hours(Rounded two decimal place) will pass before the amount of drug in the body is reduced to 100 milligrams


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2 years ago
NEED HELPS ASAP WILL GIVE BRAINLIST 100 PTS
hodyreva [135]
Hey there!

\ \ \ \ \ \ \ \ \ \Downarrow \ \Downarrow \Downarrow\ \ \ \ \Downarrow \ \ \  \ \Downarrow

\\ \\   \left[\begin{array}{ccc}  \left[\begin{array}{ccc}  \left[\begin{array}{ccc}5(4x + 2)/7y\end{array}\right] \end{array}\right] \end{array}\right]

(5)=(term) \\ \\ (sum)=(+) \\ \\ (product)= (x) \ or \ (*) \\ \\ (4)=(coefficient) \\ \\ (quotient) = (divided \ by \ symbol) \\ \\ (factor)=(2) \\ \\ \boxed{\boxed{Hope \ this \ helps}}

 
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