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Alinara [238K]
3 years ago
6

Original price:$29.99;markdown: 33 1/3% Find the retail price

Mathematics
2 answers:
faust18 [17]3 years ago
5 0

Answer:

Retail Price of the item is $ 19.99 (approx.)

Step-by-step explanation:

Given:

Original Price of an item = $ 29.99

Markdown Percentage = 33\frac{1}{3} % = \frac{33\times3+1}{3}=\frac{100}{3} %

We need to find: Retail Price

We know that Retail price = Original Price - Markdown amount

Markdown amount = \frac{\frac{100}{3}}{100}\times29.99

                               = \frac{100}{300}\times29.99

                               = \frac{2999}{300}

                               = $ 10 (approx.)

So, Retail price = 29.99 - 10 = $ 19.99

Therefore, Retail Price of the item is $ 19.99 (approx.)

-Dominant- [34]3 years ago
3 0
33.3%, move the decimal to the left twice to make it easier. then multiply 29.99 by .333. take that and subtract it from 29.99. I got 20, I'm not sure if that's right though
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Answer:

Step-by-step explanation:

sin ~a=\frac{12}{13} ,\frac{\pi}{2}

8 0
3 years ago
Peter saves $167 a month. Peter saves $37 less each month than Bill. How much will Bill save in 2 years?
Vlad [161]

Answer:

Hello! Your answer should be $2448.

Step-by-step explanation:

First, we should add 37 to 167 to find out how much money Bill makes in one month. Once we find that to be 204, we must multiply that by however many months he will be saving up for (24 months = 2 years). This will give us the expression 204 x 28, which equals 2448.

So, Bill will save $2448 in 2 years. Hope this helps!

3 0
3 years ago
Please help me with those question please help with out number 1
alina1380 [7]

Answer:

1) For each value of x, a value of y is increased by 5.

x = 0, y = 5

x = 1, y = 10

x = 2, y = 15

x = 3, y = 20

------------------------------------------------------------------------------------------

2) For each two values of x, a value of y is increased by 10.

x = 0, y = -2

x = 2, y = 8

x = 4, y = 18

x = 6, y = 28

-------------------------------------------------------------------------------------------

3)

x = 0, y = 1

x = 1, y = \frac{7}{5}

x = 5, y = 3

x = 10, y = 5

-------------------------------------------------------------------------------------------------

4)

x = 0, y = 2

x = 1, y = 17

x = 2, y = 32

x = 5, y = 77

Step-by-step explanation:

This is as easy as replacing x for the actual value show on the table.

1)

y=5x+5

When x = 0, y = ?

y=5(0)+5\\y=0+5\\y=5

When x = 1, y = ?

y=5(1)+5\\y=5+5\\y=10

When x = 2, y = ?

y=5(2)+5\\y=10+5\\y=15

When x = 3, y = ?

y=5(3)+5\\y=15+5\\y=20

-------------------------------------------------------------------------------------------------------

2)

y=5x-2

When x = 0, y = ?

y=5(0)-2\\y=0-2\\y=-2

When x = 2, y = ?

y=5(2)-2\\y=10-2\\y=8

When x = 4, y = ?

y=5(4)-2\\y=20-2\\y=18

When x = 6, y = ?

y=5(6)-2\\y=30-2\\y=28

----------------------------------------------------------------------------------------------------

3)

y=\frac{2}{5}x +1

When x = 0, y = ?

y=\frac{2}{5}(0) +1

y=0 +1\\y=1

When x = 1, y = ?

y=\frac{2}{5}(1) +1\\y=\frac{2}{5} +1

y=\frac{2}{5}+1(\frac{5}{5})\\ y=\frac{2}{5}+\frac{5}{5}  \\y=\frac{7}{5}

When x = 5, y = ?

y=\frac{2}{5}(5) +1\\y=2+1\\y=3

When x = 10, y = ?

y=\frac{2}{5}(10) +1\\y=2(2) +1\\y=4+1\\y=5

-------------------------------------------------------------------------------------------------

4)

y=15x+2

When x = 0, y = ?

y=15(0)+2\\y=0+2\\y=2

When x = 1, y = ?

y=15(1)+2\\y=15+2\\y=17

When x = 2, y = ?

y=15(2)+2\\y=30+2\\y=32

When x = 5, y = ?

y=15(5)+2\\y=75+2\\y=77

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