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2 years ago

Original price:$29.99;markdown: 33 1/3% Find the retail price

Mathematics

2 answers:

faust18 [17]2 years ago

5 0

Answer:

Retail Price of the item is $ 19.99 (approx.)

Step-by-step explanation:

Given:

Original Price of an item = $ 29.99

Markdown Percentage = $33\frac{1}{3}$ % = $\frac{33\times3+1}{3}=\frac{100}{3}$ %

We need to find: Retail Price

We know that Retail price = Original Price - Markdown amount

Markdown amount = $\frac{\frac{100}{3}}{100}\times29.99$

= $\frac{100}{300}\times29.99$

= $\frac{2999}{300}$

= $ 10 (approx.)

So, Retail price = 29.99 - 10 = $ 19.99

Therefore, Retail Price of the item is $ 19.99 (approx.)

-Dominant- [34]2 years ago

3 0

33.3%, move the decimal to the left twice to make it easier. then multiply 29.99 by .333. take that and subtract it from 29.99. I got 20, I'm not sure if that's right though

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an 8th grade slacker only has $51.26. he never dies his homework either and has to pay a 7th grader $5 for each math assignment

Marrrta [24]

Answer:

He can afford 5 language arts assignments.

Step-by-step explanation:

8 x $5 equals $40, leaving him with $11.26. $2 per assignment would cost him $10 for 5, with an extra $1.26 remaining

4 0

2 years ago

Read 2 more answers

Using the law of cosines, write an algebraic proof to show that the angles in an equilateral triangle must equal 60°. Use "∧" to

bekas [8.4K]

The algebraic proof shows that the angles in an equilateral triangle must equal 60° each

<h3>Laws of cosines </h3>

From the question, we are to use the law of cosines to write an algebraic proof that shows that the angles in an equilateral triangle must equal 60°.

Given any triangle ABC, the measures of angles A, B, and C by the law of cosines are

cos A = (b^2 + c^2 - a^2)/2bc

cos B= (a^2 + c^2 - b^2)/2ac

cos C = (a^2 + b^2 - c^2)/2ab

Now, given that the triangle is equilateral, with each of the side lengths equal to s

That is, a = b = c = s

Then, we can write that

cos A = (s^2 + s^2 - s^2)/(2s×s)

cos A = (s^2 )/(2s^2)

cos A = 1/2

cos A = 0.5

∴ A = cos⁻¹(0.5)

A = 60°

Also

cos B = (s^2 + s^2 - s^2)/(2s×s)

cos B = (s^2 )/(2s^2)

cos B = 1/2

cos B = 0.5

∴ B = cos⁻¹(0.5)

B = 60°

and

cos C = (s^2 + s^2 - s^2)/(2s×s)

cos C = (s^2 )/(2s^2)

cos C = 1/2

cos C = 0.5

∴ C = cos⁻¹(0.5)

C = 60°

Thus,

A = 60°, B = 60° and C = 60°

Hence, the algebraic proof above shows that the angles in an equilateral triangle must equal 60° each.

Learn more on The law of cosines here: brainly.com/question/2866347

#SPJ1

3 0

1 year ago

Is 2/5 greater than less than equal to 2/3 * please tell me how to do the work! And not just tell the answer bc this is a test!*

Likurg_2 [28]

Answer:

2/5 is less than 2/3

Step-by-step explanation:

bc the bottom number is how many in total and in 2/3 the number on the top only needs 1 more to be a whole.

3 0

2 years ago

Each of six jars contains the same number of candies. Alice moves half of the candies from the first jar to the second jar. Then

tino4ka555 [31]

Answer:

The number of candies in the sixth jar is 42.

Step-by-step explanation:

Assume that there are <em>x</em> number of candies in each of the six jars.

⇒ After Alice moves half of the candies from the first jar to the second jar, the number of candies in the second jar is:

$\text{Number of candies in the 2nd jar}=x+\fracx}{2}=\frac{3}{2}x$

⇒ After Boris moves half of the candies from the second jar to the third jar, the number of candies in the third jar is:

$\text{Number of candies in the 3rd jar}=x+\frac{3x}{4}=\frac{7}{4}x$

⇒ After Clara moves half of the candies from the third jar to the fourth jar, the number of candies in the fourth jar is:

$\text{Number of candies in the 4th jar}=x+\frac{7x}{4}=\frac{15}{8}x$

⇒ After Dara moves half of the candies from the fourth jar to the fifth jar, the number of candies in the fifth jar is:

$\text{Number of candies in the 5th jar}=x+\frac{15x}{16}=\frac{31}{16}x$

⇒ After Ed moves half of the candies from the fifth jar to the sixth jar, the number of candies in the sixth jar is:

$\text{Number of candies in the 6th jar}=x+\frac{31x}{32}=\frac{63}{32}x$

Now, it is provided that at the end, 30 candies are in the fourth jar.

Compute the value of <em>x</em> as follows:

$\text{Number of candies in the 4th jar}=40\\\\\frac{15}{8}x=40\\\\x=\frac{40\times 8}{15}\\\\x=\frac{64}{3}$

Compute the number of candies in the sixth jar as follows:

$\text{Number of candies in the 6th jar}=\frac{63}{32}x\\$

$=\frac{63}{32}\times\frac{64}{3}\\\\=21\times2\\\\=42$

Thus, the number of candies in the sixth jar is 42.

4 0

2 years ago

If the sales tax is 6.75%, how much tax would Adrian pay if he bought two CD's at $16.99 each and one DVD for $36.29.

Reptile [31]

CD:2 at $16.99 each=$33.98
DVD:1 at $36.29
$33.98+$36.29=
$70.27
6.75%*70.27=4.743225
round to the nearest tenth:
4.74
Andrian will pay
<u>$4.74 as sales tax </u>

6 0

2 years ago