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Natalka [10]
3 years ago
11

Angelo has a credit score of 726. According to the following

Mathematics
2 answers:
Vaselesa [24]3 years ago
8 0

Answer:

Good ( 660- 749)

Step-by-step explanation:

Because of this fact:

726 > 660 and 726 < 749

So his credit rating is considered as Good ( 660- 749)

Have a good day

Lynna [10]3 years ago
5 0

Answer:

The answer is B

Step-by-step explanation:

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What is 5/11 in decimal form? (round your answer to the nearest hundredth.)?
natita [175]
5/11 in decimal form is .45
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3 years ago
Use the line plot above to answer all 4 questions. Label your responses (a), (b), (c), and (d). When asked to explain you must u
mojhsa [17]
A) it is left skewed
B) the median is 5
C) the mean is 5.15
D) the mean would be more affected (a change of 1.05 versus a change of 0.5).

The majority of the data is to the right of the graph; this means it is left skewed.

To find the median, write all of the data values out:
2, 3, 4, 4, 5, 5, 5, 6, 6, 6, 7, 7, 7

The middle value is 5.

We find the sum of this set of values and divide by 13, the number of data points, to find the mean:
2+3+4+4+5+5+5+6+6+6+7+7+7 = 67/13 = 5.15

If we added an additional data value at 20, the new median would be 5.5.  The new mean would be (67+20)/14 = 6.2.  The mean changes more than the median.
4 0
2 years ago
Help me plz and thank you
Kay [80]
The second one - 6/21
3 0
3 years ago
Find the m∡B to the nearest tenth of a degree if cos B = 0.8926 and ∡B is an acute angle
mrs_skeptik [129]

Answer:

26.8°

Step-by-step explanation:

The cosine of an angle is the ratio of the adjacent side of the triangle in which the angle is formed to the hypotenuses side of the triangle. The cosine of the angle gives the ratio of these sides. However, the arc cosine of the ratio gives the angle measured in degrees.

If cos B = 0.8926

then arc cosine 0.8926  which may be expressed as cos-1 0.8926 will give the value of B.

B = cos-1 0.8926

= 26.8°

7 0
3 years ago
Use Newton’s Method to find the solution to x^3+1=2x+3 use x_1=2 and find x_4 accurate to six decimal places. Hint use x^3-2x-2=
luda_lava [24]

Let f(x) = x^3 - 2x - 2. Then differentiating, we get

f'(x) = 3x^2 - 2

We approximate f(x) at x_1=2 with the tangent line,

f(x) \approx f(x_1) + f'(x_1) (x - x_1) = 10x - 18

The x-intercept for this approximation will be our next approximation for the root,

10x - 18 = 0 \implies x_2 = \dfrac95

Repeat this process. Approximate f(x) at x_2 = \frac95.

f(x) \approx f(x_2) + f'(x_2) (x-x_2) = \dfrac{193}{25}x - \dfrac{1708}{125}

Then

\dfrac{193}{25}x - \dfrac{1708}{125} = 0 \implies x_3 = \dfrac{1708}{965}

Once more. Approximate f(x) at x_3.

f(x) \approx f(x_3) + f'(x_3) (x - x_3) = \dfrac{6,889,342}{931,225}x - \dfrac{11,762,638,074}{898,632,125}

Then

\dfrac{6,889,342}{931,225}x - \dfrac{11,762,638,074}{898,632,125} = 0 \\\\ \implies x_4 = \dfrac{5,881,319,037}{3,324,107,515} \approx 1.769292663 \approx \boxed{1.769293}

Compare this to the actual root of f(x), which is approximately <u>1.76929</u>2354, matching up to the first 5 digits after the decimal place.

4 0
1 year ago
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