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Gennadij [26K]
3 years ago
15

HEEEEEELP !

Mathematics
1 answer:
iogann1982 [59]3 years ago
6 0

If you meant to write y=23x-4 then none of the lines are perpendicular.

I suspect you intended y=2/3x-4, then line D, y=-3/2x-4 is perpendicular.

For any line y=mx+b, you have to "invert" m to get  a perpendicular line. Inverting in this case means: flip numerator and denominator and add a minus sign.

So 2/3 becomes -3/2, hence answer D.

The 'inverted' m is called the opposite reciprocal. That's your word of the day.


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Mario is constructing a square dart board. It will consist of a smaller square centered in a larger square. The smaller square m
Ivan

Answer:

6 inches.

Step-by-step explanation:

Let a represent side length of larger square.

We know that area of square is square of its side length, so area of the larger square will be a^2.

The area of smaller square would be 4^2.

We will use proportions to solve our given problem.

\frac{\text{Area of smaller square}}{\text{Area of larger square}}=\frac{4}{9}

\frac{4^2}{a^2}=\frac{4}{9}

\frac{16}{a^2}=\frac{4}{9}

Cross multiply:

4*a^2=16*9

\frac{4*a^2}{4}=\frac{16*9}{4}

a^2=36

Take square root:

a=\pm\sqrt{36}

a=\pm 6

Since the length cannot be negative, therefore, the side length of larger square is 6 inches.

8 0
3 years ago
I need help but not urgent but urgent!!
Mars2501 [29]

Answer:

8.6 mile

Explanation:

\sf equation \ follows : \ \ \  d = 1.2116\sqrt{h}

  • d represents the distance a person can see.
  • h represents the height above the ocean.

what the captain sees:

\hookrightarrow \sf d_c = 1.2116\sqrt{15}

what the sailor sees:

\hookrightarrow \sf d_s = 1.2116\sqrt{120}

Difference between them:

\sf \rightarrow 1.2116\sqrt{120} \  - \   1.2116\sqrt{15}

\sf \rightarrow 8.58

\sf \rightarrow 8.6      (rounded to nearest tenth)

6 0
2 years ago
Read 2 more answers
Gad has 15 trading cards that he wants to give to 5 friends. He wants each friend to have the same number of trading cards. Sele
Anastaziya [24]

Answer:

4

Step-by-step explanation:

7 0
3 years ago
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Can someone help me plz
melisa1 [442]
The answer is B,which is 454 to be exact
7 0
3 years ago
What is the domain and range of this function?
max2010maxim [7]

As for the domain, the only restriction comes from the logarithm. The argument of a logarith must be strictly positive, so we have

x-2>0 \iff x>2

As for the range, we have:

  • The range of \log(x) are all real numbers
  • If we change to \log(x-2) we're translating the function horizontally, so the range remains the same
  • If we change to \log(5(x-2() we're stretching the function horizontally, so the range doesn't change
  • If we change to \log(5(x-2))+1 we're translating the function 1 unit up, but the range is already all the real numbers, so it doesn't change.

5 0
3 years ago
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