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3 years ago

HEEEEEELP !

Mathematics

1 answer:

iogann1982 [59]3 years ago

6 0

If you meant to write y=23x-4 then none of the lines are perpendicular.

I suspect you intended y=2/3x-4, then line D, y=-3/2x-4 is perpendicular.

For any line y=mx+b, you have to "invert" m to get a perpendicular line. Inverting in this case means: flip numerator and denominator and add a minus sign.

So 2/3 becomes -3/2, hence answer D.

The 'inverted' m is called the opposite reciprocal. That's your word of the day.

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Select the graph that represents the solution to the following inequality: Ix-3I<3

Dominik [7]

The correct answer is: Answer choice: [C]:_________________________________________________→ {the number line/ graph provided for choice: [C] ; as follows}:_________________________________________________

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3 years ago

NEED HELP ASAP!!!!!!!!

NeX [460]

Answer:

Step-by-step explanation:

So you want to start by multiplying so 5×8 = 40 , 5×1=5 , 2×3=6, 7×3=21 , now you take all that and add it together 40+5+6+21

Which your answer is 72

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3 years ago

On October 1, Gary’s bank balance was $130. During October, he made two

swat32

Answer:

The first withdraw could be $30 the second could be $45 and the deposit could be $40

Step-by-step explanation:

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2 years ago

An ordered pair that makes a linear equation true is called a?

pav-90 [236]

Answer:

the solution of the equation.

Step-by-step explanation:

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2 years ago

PLZ HELP ASAP! ILL MARK BRAINLEST!

Sav [38]

Question 1.) Factor completely $12x^{4}+ 6x^{3}+18x^{2}$

Since $6$ divides all the three terms of the equation, so we take $6$ common out from the equation.

i.e., $6(2x^{4}+ 1x^{3}+3x^{2})$

Now, since $x^{2}$ divides all the three terms of the equation, so we take $x^{2}$ common out from the equation.

i.e., $6x^{2}(2x^{2}+ 1x+3)$

Now, this cannot be factored further as $2x^{2}+ 1x+3$ is a quadratic equation and taking out discriminant of it is:

$D = (1)^2 - 4(2)(3)\\ \ \ = 1- 24\\ \ \ = -23$

Since, the discriminant is less than zero. Therefore, the factored form of the given equation : $12x^{4}+ 6x^{3}+18x^{2}$ is : $6x^{2}(2x^{2}+ 1x+3)$

Question 2.) $7x^{3}y+ 14x^{2} y^{3} - 7x^{2}y^{2}$

Since $7$ divides all the three terms of the equation, so we take $7$ common out from the equation.

i.e., $7(x^{3}y+ 2x^{2} y^{3} - x^{2}y^{2})$

Now, since $x^{2}y$ divides all the three terms of the equation, so we take $x^{2}y$ common out from the equation.

i.e., $7x^{2}y(x+ 2y^{2} - y)$

Therefore, the factored form of the given equation : $7x^{3}y+ 14x^{2} y^{3} - 7x^{2}y^{2}$ is : $7x^{2}y(x+ 2y^{2} - y)$

Question 3.) What is the Greatest Common Factor of $x^{6}$ and $x^{3}$ ?

The Greatest Common Factor of two numbers is the biggest number which divides both the given numbers completely.

Now, for the expressions $x^{6}$ and $x^{3}$ :

Since, $x^{3}$ divides both the expressions completely and it is the biggest expression which divides both the expressions.

Therefore, $x^{3}$ is the Greatest Common Factor of $x^{6}$ and $x^{3}$

7 0

3 years ago

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