Given:
The rate of interest on three accounts are 7%, 8%, 9%.
She has twice as much money invested at 8% as she does in 7%.
She has three times as much at 9% as she has at 7%.
Total interest for the year is $150.
To find:
Amount invested on each rate.
Solution:
Let x be the amount invested at 7%. Then,
The amount invested at 8% = 2x
The amount invested at 9% = 3x
Total interest for the year is $150.

Multiply both sides by 100.


Divide both sides by 50.


The amount invested at 7% is
.
The amount invested at 8% is

The amount invested at 9% is

Therefore, the stockbroker invested $300 at 7%, $600 at 8%, and $900 at 9%.
Answer:
2. A
3. C
4. B
Step-by-step explanation:
2. To answer # 2, just add all the sides together...
(5x-7) + (3x-4) + (2x-6)
= 10x - 17
3. To answer # 3, divide/mulitply both the numerators and denominators by the same number and check to see if that answer matches the displayed answer...
a) 28 divided by 7 is 4, so divide the whole fraction by 7 to see if the fraction is proportional...
28/7 = 4
49/7 = 7
b) 4 goes into 16 4 times so multiply
by 4...
4 x 4 = 16
7 x 4 = 28
= 
c) 4 goes into 16 4 times so multiply the whole fraction by 4...
4 x 4 = 16
7 x 4 = 28
≠ 
d) 4 goes into 20 5 times to multiply the whole fraction by 5...
4 x 5 = 20
7 x 5 = 35

C is the answer because the fractions are not proportional.
4) 25% is a quarter of 100%. A third of 100% is 75%.
$120 - 0.25($120) = $90
Another expression for the for sale price is...
B) 0.75($120) = $90
Answer:
Step-by-step explanation:
Given
Economic system Q is given by

also 
if 



substitute these values




differentiate w.r.t to L to get 



Answer:
Step-by-step explanation:
the answer is 2 if you go to the website www.tiger-algerbra.com>drill>0.3(12x-16)=0.4(12-3x)