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fomenos
3 years ago
13

Octagon ABCDEFGH and its dilation, octagon A’B’C’D’E’F’G’H’, are shown on the coordinate plane below.

Mathematics
1 answer:
bazaltina [42]3 years ago
3 0

Answer: 2


Step-by-step explanation:


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I'm a little confused, it's about Combining like terms but I did don't understand​
ella [17]
2(-n-3)-7(5+2n)

First, you need to distribute the numbers in front of the parentheses to those in the parentheses. This means you multiply.

2 times -n= -2n

2 times -3= -6

-7 times 5= -35

-7 times 2n= -14n

This leaves you with

-2n -6 -35 -14n

Next, combine like terms.

(-2n) + (-14n)= -16n
(-35) + (-6)= -41

This gives you

-16n-41, which is B in your answer choices.

Hope this makes sense!! :)
6 0
2 years ago
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What is the formula of 2AB=2AB
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6 0
2 years ago
Both circle Q and circle R have a central angle measuring 75°. The ratio of circle Q's radius to circle R's radius is 2:5. Which
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The ratio of similar areas is the square of the ratio of the scale factor.

Circle R's sector is (5/2)² = 25/4 the area of Circle Q's sector.
7 0
3 years ago
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A square field has a side of 42 m. Find the cost of fencing its<br>boundary at Rs. 8 per metré.​
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2 years ago
The figure below shows square ABCD inscribed on square PQRM on a coordinate plane. Which of the following expressions represents
vova2212 [387]
The hypotenuse of the triangle is given by:
 CB ^ 2 = RC ^ 2 + RB ^ 2&#10;
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 CB ^ 2 = 2 ^ 2 + 4 ^ 2&#10;
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 CB = \sqrt{ 2 ^ 2 + 4 ^ 2}  &#10;&#10; CB = \sqrt{ 4 + 16}  &#10;&#10; CB = \sqrt{20}  &#10;&#10; CB = \sqrt{4*5}  &#10;&#10; CB = 2\sqrt{5}  &#10;&#10;&#10;&#10;
 Then, the perimeter of the triangle is:
 P = RB + RC + CB&#10;
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 the perimeter of triangle BRC in units is:
 D.6 + 2√5
7 0
2 years ago
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