4028 mi 2< M is the expression you were looking for i think
Answer:
The ball will reach a height of 5 ft by the 4th time.
Step-by-step explanation:
The initial height of the ball is 40 ft, when it bounces from the floor once the height will be 20 ft, the second time it'll be 10 ft, and so on. The sequence that can represent the maximum height of the ball after each bounce is:
{40, 20, 10,...}
This kind of sequence is called a geometric progression, in this kind of progression the next number is related to the one before it by the product of a constant called ratio, in this case 1/2. To calculate a specific position in this sequence we only need the ratio and the first number, using the formula below:
a_n = a*r^(n-1)
Where n is the position we want to know, a is the first number and r is the ratio. In this case we have:
a_4 = 40*(1/2)^(4-1) = 40*(1/2)^3 = 40/8 = 5
The ball will reach a height of 5 ft by the 4th time.
16cm x 60 would give you the centimeters per hour
16 x 60 = 960cm
= 9.6m
(There are 60 minutes in an hour which is how i got that number)
Since the formula for interior angles is 180 x (n-2), n being the amount of sides of the polygon, you replace n with 35, and you get this:
180 x (35-2), or 180 x 33, which equals 5940
